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2 years ago

Find several points that are on the graph of the function y = x^2 + 1. Plot the points in a coordinate plane.

Mathematics

1 answer:

beks73 [17]2 years ago

8 0

Answer:

Below.

Step-by-step explanation:

Plot following points.

Calculate the point by plugging in values of x into x^2 + 1

for example When x = 0, y = 0^1 + 1 = 1.

So plot plot (0, 1),

Make a table of points to plot:

x -3 -2 -1 0 1 2 3

y 10 5 2 1 2 5 10

When you plot the points you'll see the graph is U shaped.

The function is of second degree (as it contains x^2) so it wont be linear.

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The ratio of pencils to pens in the drawer is 8:14. If there are actually twice as many pencils as in the ratio, how many pencil

dusya [7]

Yo sup??

let the number of pencils and pens be 8x and 14x

x=2

therefore the number of pens and pencils are

16 pencils and 28 pens

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3 years ago

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torisob [31]

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2 years ago

If y=14 when x=20, find x when y=3.5

Kruka [31]

I hope this helps you

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2 years ago

Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

(a) Length of AB

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

(b) Are AB and CD congruent

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

(c) AB bisects CD or not?

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

(d) CD bisects AB or not?

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

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mylen [45]

85 is the correct answer.

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