The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
The answer would be 50 and 37.
50-37 = 13
50+37 = 87
Answer:
(-5.77, 6.46)
Step-by-step explanation:
15x + 9y = 45 ----------- i
9x + 8y = 12----------------ii
Multiply equation i by 9 the coefficient of x in equ ii
And equation ii by 15 the coefficient of x in equ I
9 x 15x + 9y = 45 ----------- i
15 x 9x + 8y = 12----------------ii
135x+81y = 405
135x+120y= 180
Subtract equation ii from I
135x-135x+81y-(+120y)= 405-180
-39y=225
y = 225/-39 = -5.77
Insert the value of y in equ i
15x + 9y = 45
15x+9(-5.77) = 45
15x-51.92=45
15x = 45+51.92
15x= 96.92
x = 96.92/15= 6.46
(x,y) = (-5.77, 6.46)
x = 6.92/15
Answer:
As x ⇒-∞, P(x) ⇒ -∞
As x ⇒ ∞, P(x) ⇒ ∞
Step-by-step explanation:
To find left hand end behavior, plug in negative infinity into the function and evaluate...
P(x) = 3(-∞) = -3(∞) = -∞
The 'y' values of the function decrease towards negative infinity as the 'x' values approach negative infinity
P(x) = 3(∞) = ∞
The 'y' values of the function increase towards positive infinity as the 'x' values approach positive infinity
Answer:0.3+0.05
Step-by-step explanation:
