Answer:
0.93g/mL
Explanation:
Given parameters
Mass of wood = 3.16g
Initial volume of water = 20mL
Volume of water + wood = 23.4mL
Unknown:
Density of the wood = ?
Solution:
Density is the mass per volume of a substance.
It is mathematically expressed as;
Density =
Volume of wood = 23.4mL - 20mL = 3.4mL
So,
Density =
= 0.93g/mL
The answer is visible rays. For example, when a rain storm stops, the sun comes out and you are likely to see a rainbow. This is because the sun shines on water molecules in the air and the colors appear. These colors are called visible light. The only ray that a naked Human eye can see
Answer:
MnO- Manganese Oxide
Explanation:
Empirical formula: This is the formula that shows the ratio of elements
present in a
compound.
How to determine Empirical formula
1. First arrange the symbols of the elements present in the compound
alphabetically to determine the real empirical formula. Although, there
are exceptions to this rule, E.g H2So4
2. Divide the percentage composition by the mass number.
3. Then divide through by the smallest number.
4. The resulting answer is the ratio attached to the elements present in
a compound.
Mn O
% composition 72.1 27.9
Divide by mass number 54.94 16
1.31 1.74
Divide by the smallest number 1.31 1.31
1 1.3
The resulting ratio is 1:1
Hence the Empirical formula is MnO, Manganese oxide
The molarity of a solution is the number of moles of a substance divided by the volume in liters prepared.
, where n is number of moles and V is the volume in liters.
In order to calculate the mass of solute we need to convert the volume and molarity to moles
![1.421 L solution \times\frac{0.0730 moles}{1 Lsolution}= 1.037 mol NaCO_3](https://tex.z-dn.net/?f=1.421%20L%20solution%20%5Ctimes%5Cfrac%7B0.0730%20moles%7D%7B1%20Lsolution%7D%3D%201.037%20mol%20NaCO_3)
Now that we have moles we use the relative formula mass of NaCO₃, We have 1 Na atom, 1 C atom and 3 O atoms, thus
![M_r= (1\times 22.99) + (1\times 12.00) + (3\times 16.00)= 82.99g/mol](https://tex.z-dn.net/?f=M_r%3D%20%281%5Ctimes%2022.99%29%20%2B%20%281%5Ctimes%2012.00%29%20%2B%20%283%5Ctimes%2016.00%29%3D%2082.99g%2Fmol)
![1.037 \times\frac{82.99g}{mol} = 86.1g](https://tex.z-dn.net/?f=1.037%20%5Ctimes%5Cfrac%7B82.99g%7D%7Bmol%7D%20%3D%2086.1g)
Answer:
high density
Explanation:
just got it right on edge