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3 years ago

using the aufbau principle,write the electronic configuration for the ground state of the atom having atomic number 1 to 30

Chemistry

1 answer:

Elina [12.6K]3 years ago

8 0

Aufbau principle:

Electrons are added one at a time from the lowest energy orbitals available until all the orbitals are filled.

According to the Aufbau principle, electrons fill lower energy orbitals first.

(i) Boron (Z = 5)

Electronic configuration =

(ii) Neon (Z = 10)

Electronic configuration =

(iii) Aluminium (Z = 13)

Electronic configuration =

(iv) Chlorine (Z = 17)

Electronic configuration =

(v) Calcium (Z = 20)

Electronic configuration =

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Answer:

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2 years ago

An organic compound of relative molecular mass 46,on analysis was found to contain 52.0% carbon, 13.3% hydrogen and 34.7% oxygen

Nadya [2.5K]

Answer:

Empirical formula is C₂H₆O.

Explanation:

Empirical formula:

It is the simplest formula gives the ratio of atoms of different elements in small whole number

Given data:

Percentage of hydrogen = 13.3%

Percentage of carbon = 52.0%

Percentage of oxygen = 34.7%

Empirical formula = ?

Molecular formula = ?

Solution:

Number of gram atoms of H = 13.3 / 1.01 = 13 .17

Number of gram atoms of O = 34.7 / 16 = 2.17

Number of gram atoms of C = 52.0 / 12 = 4.3

Atomic ratio:

C : H : O

4.3/2.17 : 13.17/2.17 : 2.17/2.17

2 : 6 : 1

C : H : O = 2 : 6 : 1

Empirical formula is C₂H₆O.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

n = 46 / 158

The relative molecular mass of compound is not correct.

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3 years ago

After chlorofluorocarbons we’re banned, which class of chemicals was used in their place

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Answer:

Hydrofluorocarbons

Explanation:

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4 years ago

Read 2 more answers

How many milliliters of 2.5 M HCl are required<br> to exactly neutralize 1.5 L of 5.0 M NaOH?

Airida [17]

Answer:

3000mL

Explanation:

The following data were obtained from the question:

Volume of acid (Va) =..?

Molarity of acid (Ma) = 2.5M

Volume of base (Vb) = 1.5L

Molarity of base (Mb) = 5M

Next, we shall write the balanced equation for the reaction. This is given below:

HCl + NaOH —> NaCl + H2O

From the balanced equation above,

We obtained the following:

Mole ratio of the acid (nA) = 1

Mole ratio of base (nB) = 1

Next, we shall determine the volume of HCl needed for the reaction. This can be obtained as follow illustrated below:

MaVa / MbVb = nA/nB

2.5 x Va / 5 x 1.5 = 1

Cross multiply

2.5 x Va = 5 x 1.5

Divide both side by 2.5

Va = 5 x 1.5 / 2.5

Va = 3L

The volume of the acid required is 3L.

Finally, we shall convert the volume of the acid from litre (L) to millilitre (mL). This is illustrated below:

1L = 1000mL

Therefore, 3L = 3 x 1000 = 3000mL.

Therefore, the volume of the acid, HCl in mL needed fi4 the reaction is 3000mL

7 0

4 years ago

Use the following equation to answer the questions below:

Gala2k [10]

Explanation:

The equation of the reaction is given as;

Be + 2HCl → BeCl2 + H2

What is the mass of beryllium required to produce 25.0g of beryllium chloride?

1 mol of Be produces 1 mol of BeCl2

Converting to mass;

Mass = Molar mass * Number of moles

9.01g of Be produces 79.92g of BeCl2

xg of Be produces 25g of BeCl2

Solving for x;

x = 25 * 9.01 / 79.92

x = 2.82 g

What is the mass of hydrochloric acid required to produce 25.0g of beryllium chloride? g

Converting 25.0g of beryllium chloride to moles;

Number of moles = Mass / Molar mass

Number of moles = 25 / 79.92 = 0.3128 mol

2 mol of HCl produces 1 mol of BeCl2

x mol of HCl would produce 0.3128 mol of BeCl2

solving for x;

x = 0.3128 * 2 = 0.6256 mol

Converting to mass;

Mass = 0.6256 * 36.5 = 22.83 g

What is the mass of hydrogen gas produced when 25.0g of beryllium chloride is also produced? g

25g of BeCl2 = 0.3128 mol of BeCl2

From the equation;

1 mol of H2 is produced alongside 1 mol of BeCl2

This means;

0.3128 mol of H2 would also be produced alongside 0.3128 mol of BeCl2

Mass = Number of moles * Molar mass

Mass = 0.3128mol * 2.0159 g/mol = 0.6306 g

3 0

3 years ago

using the aufbau principle,write the electronic configuration for the ground state of the atom having atomic number 1 to 30​

using the aufbau principle,write the electronic configuration for the ground state of the atom having atomic number 1 to 30