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AURORKA [14]
3 years ago
13

What is the relationship among energy, work and power

Physics
1 answer:
horsena [70]3 years ago
6 0

Answer:

Power is the rate of using energy or doing work. Energy is measuredin Joules. Power is measured in Joules per second or Watts. Work can be defined as transfer of energy

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A cart traveling at 0.3 m/s collides with stationary object. After the collision, the cart rebounds in the opposite direction. T
miv72 [106K]

Answer:

C.   In the first collision has twice the momentum as when it stays still ( second colllions)

Explanation:

To see which statement is correct, it is best to solve the problem, the momentum is equal to the variation of the moment

     I = Δp = m vf - m v₀

     I = m (vf -v₀)

Case 1. In car bounces, the initial speed is 0.3 m / s, say that this direction is positive, when the magnitude of the speed bounces it remains constant, but its direction is reversed (vf = -0.3 m / s)

    I₁ = m (-0.3 - 0.3)

    I₁ = -0.6 m

Case 2. The expensive one that still after the crash so its speed is zero (vf = 0)

    I₂ = m (0 - 0.3)

    I₂ = -0.3 m

Let's calculate the relationship between the two impulses

     I₁ / I₂ = -0.6m / -0.3m

     I₂ / I₂ = 2

When it bounces it has twice the momentum as when it stays still

Now let's analyze the answers:

A.   False The momentum changes

B. False. The momentum is less in the second collision

C. True.  The momentum is double in this collision

D. False. Can be calculated, because the mass is the same throughout the exercise and is eliminated in the equations

E. False.  When they say bounces it implies the same speed with the opposite direction

4 0
3 years ago
Will mark the brainliest
Gennadij [26K]

Answer:

OK draw a diagram - you have the force from (b) acting sown the slope and a component of the weight. Use F=ma to get the deceleration and then use SUVAT. Post your working if this doesn't work.

friction = 900N

braking = 3100N

total = 4000N

w= mxg = 1000*9.81= 9810N

total = 9810 + 4000 = 13810N

force/mass = 13810/1000 = 13.81ms^-2

then using v^2 = u^2 + 2as, i get s as 14 but it is incorrect

Explanation:

4 0
3 years ago
If the Test Section area has an air speed of 10 m/s, what would be the air speed at the Air Intake area
FrozenT [24]

The speed of air at the intake area is \frac{10A_2}{A_1} (m/s).

<h3 /><h3>Continuity equation</h3>

The continuity equation is used to determine the flow rate at different sections of a pipe or fluid conduit.

The continuity equation is given as;

A_1v_1 = A_2 v_2

  • Let the intake area = A₁
  • Let the velocity of air in intake area = v₁
  • Let the area of the test section = A₂
  • Velocity of air in test section, v₂ = 10 m/s

The speed of air at the intake area is calculated as follows;

A_1 v_1 = A_2 v_2\\\\&#10;v_1 = \frac{A_2 v_2}{A_1} \\\\&#10;v_1 = \frac{10A_2}{A_1}

Learn more about continuity equation here: brainly.com/question/14619396

4 0
3 years ago
Plz help me find the answers
san4es73 [151]

Answer: Plastids are the site of manufacture and storage of important chemical compounds used by the cells of autotrophic eukaryotes

Explanation:

6 0
3 years ago
Read 2 more answers
Can someone please help me on this
Triss [41]

Answer:

I am on the same question and I’m lost

Explanation:

4 0
3 years ago
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