I need help with #24 ASAP .. I have to get it done today.. I need help with #24 right now... I'm not playing no games right now

If an airplane were traveling westward with a thrust force of 450 N and there was a headwind (drag) of 200 N, what would the res

Marat540 [252]

Answer:

The resulting net force on the airplane would be 250N.

Explanation:

It would be 250N because to find the amount of Newtons you would have to do 450 minus 200. 450 minus 200 equals 250. You can check by adding 200 plus 250 and it equals 450 the which is the "thrust".

6 0

2 years ago

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A pressure cooker cooks a lot faster than an ordinary pan by maintaining a higher pressure and temperature inside. the lid of a

BlackZzzverrR [31]

Answer:

$m=40.816\ gm$

Explanation:

Given;

The operational pressure of the cooker, $P=10^5\ Pa (gauge)$

area of the opening, $a=4\ mm^2$

We know that the gauge pressure is measured with respect to the atmospheric pressure. As the atmospheric pressure acts on all the components of the system being observed so, we only need to counter the gauge pressure.

As the petcock sits on the opening of the cross-section so, it balances the built-in pressure due to its weight.

Hence:

$m.g=P\times a$

where:

$m=$ mass of the petcock

$g=$ acceleration due to gravity

$m\times 9.8=10^5\times 4\times 10^{-6}$

$m=40.816\ gm$

6 0

3 years ago

Badri makes the table below to review the factors that affect the electric force between objects. Which change will correct the

kirill115 [55]

Answer:

Changing "Mass" to "Amount of electric charge"

4 0

4 years ago

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Waves are created on the surface of water when we drop a stone into it. Similarly you must have seen the waves generated on a st

antoniya [11.8K]

Answer:

gdfhf

Explanation:

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5 0

3 years ago

An open container holds ice of mass 0.555 kg at a temperature of -16.6 ∘C . The mass of the container can be ignored. Heat is su

s2008m [1.1K]

Answer: A. 23.59 minutes.

B. 249.65 minutes

Explanation: This question involves the concept of Latent Heat and specific heat capacities of water in solid phase.

Latent heat of fusion is the total amount of heat rejected from the unit mass of water at 0 degree Celsius to convert completely into ice of 0 degree Celsius (and the heat required for vice-versa process).

Specific heat capacity of a substance is the amount of heat required by the unit mass of a substance to raise its temperature by 1 kelvin.

Here, given that:

mass of ice, m= 0.555 kg

temperature of ice, T= -16.6°C

rate of heat transfer, $q=820 J.min^{-1}$

specific heat of ice, $c_{i}= 2100 J.kg^{-1}.K^{-1}$

latent heat of fusion of ice, $L_{i}=334\times10^{3}J.kg^{-1}$

Asked:

1. Time require for the ice to start melting.

2. Time required to raise the temperature above freezing point.

Sol.: 1.

We have the formula:

$Q=mc\Delta T$

Using above equation we find the total heat required to bring the ice from -16.6°C to 0°C.

$Q= 0.555\times2100\times16.6$

$Q= 19347.3 J$

Now, we require 19347.3 joules of heat to bring the ice to 0°C and then on further addition of heat it starts melting.

∴The time required before the ice starts to melt is the time required to bring the ice to 0°C.

$t=\frac{Q}{q}$

$=\frac{19347.3}{820}$

= 23.59 minutes.

Sol.: 2.

Next we need to find the time it takes before the temperature rises above freezing from the time when heating begins.

Now comes the concept of Latent heat into the play, the temperature does not starts rising for the ice as soon as it reaches at 0°C it takes significant amount of time to raise the temperature because the heat energy is being used to convert the phase of the water molecules from solid to liquid.

From the above solution we have concluded that 23.59 minutes is required for the given ice to come to 0°C, now we need some extra amount of energy to convert this ice to liquid water of 0°C.

We have the equation: latent heat, $Q_{L}= mL_{i}$

$Q_{L}= 0.555\times334\times10^{3}= 185370 J$

Now the time required for supply of 185370 J:

$t=\frac{Q_{L}}{q}$

$t=\frac{185370}{820}$

t= 226.06 minutes

∴ The time it takes before the temperature rises above freezing from the time when heating begins= 226.06 + 23.59

= 249.65 minutes

8 0

3 years ago