Answer:
1.6 pF
Explanation:
The capacitance of a parallel-plate capacitor in air is given by:
where
is the vacuum permittivity
A is the area of each plate
d is the separation between the plates
In this problem we have:
- Separation between the plates: d = 5.00 mm = 0.005 m
- Area of the plates:
Therefore, the capacitance is
Answer:
Explanation:
a ) Slit separation d = .1 x 10⁻³ m
Screen distance D = 4 m
wave length of light λ = 650 x 10⁻⁹ m
Width of central fringe = λ D / d
=
= 26 mm
b ) Distance between 1 st and 2 nd bright fringe will be equal to width of dark fringe which will also be equal to 26 mm
c ) Angular separation between the central maximum and 1 st order maximum will be equal to angular width of fringe which is equal to
λ / d
=
= 6.5 x 10⁻³ radian.