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3 years ago

How many joules are required to boil 150. grams of water?

1 answer:

3 0

Ans: 47,070 J

Thus, 47,070 J are needed to increase the temperature of 150 g of water from 25 degrees C to its boiling point of 100 degrees C. One can follow a similar procedure to determine the energy needed to heat water from one temperature to another.

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To prevent rust, nails are coated with ________. To prevent rust, nails are coated with ________. salt calcium lithium sodium zi

Arturiano [62]

Answer:

the answer to this question is zinc

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3 years ago

Which is a characteristic of nuclear fusion but NOT nuclear fission?

egoroff_w [7]

I think c is used in electric power plants.

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3 years ago

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Which of the following is not true? a. The freezing point of sea water is lower than the freezing point of pure water. b. The bo

Anna007 [38]

Answer:

The false statement is b.

The boiling point of a water sample from the Salt Lake is lower than the boiling point of pure water

Explanation:

This excersise refers to colligative properties.

Boiling point refers to the property of boiling point elevation. In a solution of ions, as water sea or water from lakes, the boiling point will be higher than water pure.

It is logical to say that, because these sort of water have ions. Remember that colligative properties depends on the solute particles.

T° boiling solution - T° pure solvent = Kb . m . i

In the freezing point depression, we have the oppossite of boiling point elevation. Freezing point of solution is lower than pure solvent, according to this:

T° freezing pure solvent - T° freezing solution = Kc . m . i

We have to always consider the i, which means Van't Hoff factor, number of ions dissolved in solution. As the i is higher, the freezing point of solution will be lower, and the boiling point of solution will be higher.

They are true statement a and c.

In solution of., [NaCl] = 0.1M, as it is a higher concentration, the molality is also higher than a solution of [NaCl] = 0.05.

As water sample form Salt Lake has certain ions, it is logical to say that the boiling point of this water is higher than boiling point of pure water.

5 0

3 years ago

Consider the reaction 2 S + 3 O2 â†’ 2 SO3 , which has a 75.1% yield. How much O2 is consumed if 583 g of SO3 are produced?

Ymorist [56]

Answer:

A/1. 10.9 mol O2

Explanation:

583 g x 1 mol SO3 x 3 mol O2 /

80.057 g mol SO3 x 2 mol SO3

- You just need to find molar mass of SO3, which is 80.057 g.

- Everything else came from formula. Further explanation...

- Always start with what they give, such as 583 g. Then find 1 mol of what is being produced, in this it is SO3. We already found this because we did molar mass above. Next. find how many moles of what they want, which is O2. Look in equation and you can see 3 mol in from of O2. Next, do the same for SO3 and you can find 3 mol in front of that. Lastly, just do the math.

- If you need a further explanation or more help on any problems I would be happy to help, just let me know.

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3 years ago

Identify the ion ratios needed to form neutral compounds from the ions below. The metal ion (cation) is listed first, and the no

Natasha2012 [34]

To figure out the ratios of these compounds, it is important to remember that the charge of these compounds must be <em>neutral</em>.

So in order to make them neutral, you must have specific ratios:

$Na^{+}: Br^{-} =1:1$ ; This is true because they both have a charge of magnitude of 1.

$Al^{3+}: Cl^{-}=1:3$ ; We need 3 chlorine atoms because we need to balance out the charge from the 3+ charge of aluminum - therefore since chlorine has a 1- charge, we need 3 atoms.

$Mg^{2+}: O^{2-}=1:1$ ; The charges of the magnesium (2+) are balanced with the oxygen charge (2-).

$Al^{3+}: O^{2-}=2:3$ ; This is correct because if charges are like this, you must find the least common factor in order to know the ratio. The LCF is 6, therefore, for the atom with a 3+ charge, you need 2 of them, and for the atom with a 2- charge, you need 3 of them. This keeps the charge neutral.

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3 years ago

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