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elena55 [62]
4 years ago
10

A sample of solid NH 4HS is placed in a closed vessel and allowed to equilibrate. Calculate the equilibrium partial pressure (at

m) of ammonia, assuming that some solid NH 4HS remains.
Chemistry
1 answer:
UNO [17]4 years ago
5 0

Answer:

The answer to the question is

The equilibrium partial pressure (atm) of ammonia, assuming that some solid NH₄HS remains 0.26 atm.

Explanation:

To solve the question, we write out the chemical equation as follows

NH₄HS (s) ⇄ NH₃ (g) + H₂S (g)

From the above equation, it is observed that only the gaseous products contribute to the partial pressure

Kp =PNH₃·PH₂S where at Kp = 0.070 and PNH₃, PH₂S are the partial pressures of the gases

However since the number of moles of both gases are equal, therefore by Avogadro's law PNH₃ = PH₂S

Then PNH₃  = √(0.07) = PH₂S = 0.2645 atm. ≅ 0.26 atm.

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Marat540 [252]

Answer : The partial pressure of helium is, 1.815\times 10^4KPa

Solution : Given,

Molar mass of O_2 = 32 g/mole

Molar mass of helium = 4 g/mole

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Total pressure of gas = 2.07\times 10^4KPa

As we are given gases in percent, that means 10 g of oxygen gas, 50 g of helium gas and 40 g of nitrogen gas present in 100 g of mixture.

First we have to calculate the moles of oxygen, helium and nitrogen gas.

\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{10g}{32g/mole}=0.3125moles

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\text{Moles of }N_2=\frac{\text{Mass of }N_2}{\text{Molar mass of }N_2}=\frac{40g}{28g/mole}=1.428moles

Now we have to calculate the total number of moles of gas mixture.

\text{Total number of moles of gas}=\text{Moles of oxygen gas}+\text{Mole of helium gas}+\text{Moles of nitrogen gas}

\text{Total number of moles of gas}=0.3125+12.5+1.428=14.24moles

Now we have to calculate the moles fraction of helium gas.

\text{Mole fraction of He gas}=\frac{\text{Moles of He gas}}{\text{Total number of moles of gas}}=\frac{12.5}{14.25}=0.877

Now we have to calculate the partial pressure of helium.

p_{He}=X_{He}\times P_T

where,

p_{He} = partial pressure of helium

P_T = total pressure

X_{He} = mole fraction of helium

Now put all the given values in this formula, we get

p_{He}=(0.877)\times (2.07\times 10^4KPa)=1.815\times 10^4KPa

Therefore, the partial pressure of helium is, 1.815\times 10^4KPa

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Answer:

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Explanation:

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