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zheka24 [161]
3 years ago
14

A chef got 7 bags of onions. The red onions came in bags of 8 and the yellow onions came in bags of 3. If the chef got a total o

f 41 onions, how many bags of each type of onion did he get?
Mathematics
1 answer:
frutty [35]3 years ago
5 0

Answer:

\#\text{ of 8-onion bags: }4,\\\#\text{ of 3-onion bags: }3

Step-by-step explanation:

Let a be the number of bags with 8 onions and let b be the number of bags with 3 onions. We have the following system of equations:

\begin{cases}a+b=7,\\8a+3b=41\end{cases}

Subtracting b from both sides of the first equation, we get a=7-b. Substitute this into the second equation:

8(7-b)+3b=41,\\56-8b+3b=41,\\56-5b=41,\\-5b=-15,\\b=\boxed{3}

Therefore, the number of 8-onion bags is:

a=7-b,\\a=7-3,\\a=\boxed{4}

Thus, the chef got 4 8-onion bags and 3 3-onion bags.

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