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2 years ago

What is the measure of ∠L ?

Mathematics

2 answers:

MissTica2 years ago

5 0

I got m∠L=72.54 since arccos(18/60)= <span>72.5423968763</span>.

Marizza181 [45]2 years ago

4 0

Answer:

$m$

Step-by-step explanation:

we know that

In the right triangle LMN

$cos(L\°)=\frac{LM}{LN}$ -----> adjacent side to angle L divided by the hypotenuse

substitute the values

$cos(L\°)=\frac{18}{60}$

$(m$

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2 years ago

an aeroplane is flying with a help of 300 km per hour who much distance will it cover in 160 minute

uysha [10]

Answer:

800 km

Step-by-step explanation:

Does the plane have a speed of it's own? I don't see it, so will assume the plane is simply travelling at 300 km/h.

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1 year ago

For a chemistry experiment Laura needs 300 ml of a 15% sulphuric acid solution. The Science Department has quantities of 5% acid

Len [333]

Answer:

100 ml of 5% solution

200 ml of 20% solution

Step-by-step explanation:

x = amount of 5% solution

y = amount of 20% solution

System of equations:

x + y = 300

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7 0

2 years ago

Read 2 more answers

Double Delicious Bakery sells a dozen double chocolate dounts for $7.80

KonstantinChe [14]

Answer:

A) each donut costs $0.65

B) the price for 1 and 1/2 dozen of donuts (18 donuts) is $11.70

Step-by-step explanation:

For a you have to divide $7.80 by 12 (since its a dozen) and thats how you get $0.65

For b you have to multiply the price of each donut ($0.65) by the 1 and 1/2 dozen (18 donuts) and thats how you get $11.70

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3 years ago

Let f be strictly convex. If f has a minimum, show that it is unique. (Hint: assume there are two minima x1, x2 and derive a con

IrinaK [193]

Answer: Ok, i will use the hint provided.

We call x1 and x2 to te two mínima of f, that is $\frac{df}{dx} (x1) = 0, \frac{df}{dx} (x2) = 0$ .

The convexity condition says that, if f is differentiable, then the graph of f(x) lays above all the tangents between X and Y, if Y>X then

$f(Y) \geq f(X) + f'(X)*(Y-X)$ where $f'(x) = \frac{df}{dx} (x)$ .

then, if we took Y = x1 and X = x2, we have $f(x1) \geq f(x2)$ because f'(x2) = 0.

now if we took Y = x2 and X = x1, we have $f(x2) \geq f(x1)$ because f'(x1) = 0.

Then, x1 = x2. Which implies that we only have one minima.

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3 years ago