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OLga [1]
2 years ago
10

Help i'll give you brainlyest

Mathematics
1 answer:
zhannawk [14.2K]2 years ago
7 0

Answer:

Its not A and B and I know that, but can you show the rest so I can see if its C because the rest of the picture isn't there

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a sum of RS 500 is in the form of denominators of RS5 & RS 10..if the total no. of notes is 90 ,find the no. of notes of eac
Katarina [22]
Let rs.5 denominations be x , then rs 10 denominations will be 90-x

then total amount 5x + 10(90-x) which is rs.500

 5x + 10(90-x) = 500

900 - 5x = 500
400 = 5x
therefore x = 80
          therefore no. of rs.5 is 80
no. of rs.10 is 90-x = 90-80 = 10

8 0
3 years ago
What is the slope of this line?
White raven [17]

Answer:

<em>m</em> = 0

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

  • Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points given from the graph.</em>

Point (0, 2)

Point (7, 2)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{2-2}{7-0}
  2. Subtract:                       m=\frac{0}{7}
  3. Divide:                          m=0

Any horizontal line will have a slope of 0.

And we have our final answer!

3 0
3 years ago
Help me please fast ​
Natalija [7]

Answer:

Step-by-step explanation:

\frac{5}{x-3}+\frac{2}{x+1}=3  \\\\\frac{5(x+1)+2(x-3)}{(x-3)(x+1)} =3\\\\5x+5+2x-6=3(x-3)(x+1)\\\\7x-1=3(x^2+x-3x-3)\\\\7x-1=3(x^2-2x-3)\\\\7x-1=3x^2-6x-9\\\\0=3x^2-6x-7x-9+1\\0=3x^2-13x-8

Hence proved!

3 0
3 years ago
Which weights are within 2 standard deviations of the mean? select three options. 8.4 lbs 8.9 lbs 9.5 lbs 10.4 lbs 10.9 lbs
djverab [1.8K]

The weights are within 2 standard deviations of the mean are 8.9 lbs, 9.5 lbs and 10.4 lbs

<h3>How to determine the weights?</h3>

The given parameters are:

  • Mean, μ = 9.5
  • Standard deviation, σ = 0.5

The weights within 2 standard deviation is represented as:

μ - 2σ ≤ x ≤ μ + 2σ

Substitute known values

9.5 - 2(0.5) ≤ x ≤ 9.5 + 2(0.5)

Evaluate the product

9.5 - 1 ≤ x ≤ 9.5 + 1

Evaluate the sum

8.5 ≤ x ≤ 10.5

This means that the weights are between 8.5 and 10.5 (inclusive)

Hence, the weights are within 2 standard deviations of the mean are 8.9 lbs, 9.5 lbs and 10.4 lbs

Read more about standard deviation at:

brainly.com/question/11743583

5 0
2 years ago
I need whats in the red rectangle
lorasvet [3.4K]

Answer:

9

Step-by-step explanation:

sqrt(5) + sqrt(405)

sqrt(5) + sqrt( 81*5)

sqrt(5) + sqrt(81) sqrt(5)

sqrt(5) +9 sqrt(5)

10 sqrt(5)

3 0
3 years ago
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