Let us compute first the probability of ending up an odd number when rolling a dice. A dice has faces with numbers 1 up to 6. The odd numbers within that is 3 (1, 3 and 5). Therefore, each dice has a probability of 3/6 or 1/2. Then, you use the repeated trials formula:
Probability = n!/r!(n-r)! * p^r * q^(n-r), where n is the number of tries (n=6), r is the number tries where you get an even number (r=0), p is the probability of having an even face and q is the probability of having an odd face.
Probability = 6!/0!(6!) * (1/2)^0 * (1/2)^6
Probability = 1/64
Therefore, the probability is 1/64 or 1.56%.
Answer: $19
Step-by-step explanation:
589 divide by 31 = 19
The answer is A because 48.2 +39.4.6 is 87.6
Ill write A for alpha and B for beta.
AB = c/a and A + B = -b/a
A^4 + B^4 = (A^2 + B^2)^2 - 2A^2B^2
= [(A + B)^2 - 2AB] ^2 - 2A^2B^2
Plugging in the values for A+B and AB we get
A^4 + B^4 = [(-b/a)^2 - 2c/a]^2 - 2(c/a)^2
= (b^2 / a^2 - 2c / a)^2 - 2c^2/a^2
= (b^2 - 2ac)^2 - 2c^2
---------------- -----
a^4 a^2
= (b^2 - 2ac)^2 - 2a^2c^2
-----------------------------
a^4
Answer:
C is the right answer
Step-by-step explanation:
In this case we have the events
<em>A: The subject is telling the truth.
</em>
<em>B: The the polygraph indicates that the subject is lying
</em>
Recall that P(B|A) is defined as the probability that the event B occurs given that the event has already occurred, and is equals to P(B∩A)/P(A).
So, with the events we have defined, <em>P(B|A) indicates the probability that the polygraph indicates lying given that the subject is actually telling the truth.
</em>
The most suitable answer is thus, C
