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VladimirAG [237]
3 years ago
13

Kyle bought x candy bars. He paid $0.89, including tax, per candy bar. He gave the cashier $10 and received $3.77 in change. How

many candy bars did Kyle purchase?
Mathematics
2 answers:
PIT_PIT [208]3 years ago
4 0

Answer:

I think 7

Step-by-step explanation:

aleksandr82 [10.1K]3 years ago
4 0

Answer:

Without tax, it is 7. How much is the tax?

Step-by-step explanation:

10.00 - 3.77 = 6.23

0.89 x 7 = 6.23

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Answer:

b) 95%

Step-by-step explanation:

We have been given that scores on an approximately bell shaped distribution with a mean of 76.4 and a standard deviation of 6.1 points. We are asked to find the percentage of the data that is between 64.2 points and 88.6 points.

First of all, we will find z-scores of each data point as:

z=\frac{x-\mu}{\sigma}

z=\frac{64.2-76.4}{6.1}

z=\frac{-12.2}{6.1}

z=-2

Let us find z-score corresponding to normal score 88.6.

z=\frac{88.6-76.4}{6.1}

z=\frac{12.2}{6.1}

z=2

To find the percentage of the data is between 64.2 points and 88.6 points, we need to find area under a normal distribution curve that lie within two standard deviation of mean.

The empirical rule of normal distribution states that approximately 95% of data points fall within two standard deviation of mean, therefore, option 'b' is the correct choice.

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4 years ago
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matrenka [14]

Answer:

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3 years ago
Find all the values of x in the set of complex numbers that satisfy the following equation:
Fynjy0 [20]
Compute all the component integrals first:

I_1=\displaystyle\int_0^{\pi/4}2\sec x\,\mathrm dx=2\ln(\sqrt2+1)
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I_3=\displaystyle\lim_{a\to\infty}\int_{-a}^a\frac{\mathrm dx}{x^2+1}=\pi

Now,

\sqrt2\approx1.4\implies \sqrt2+1\approx2.4
\implies \left\lceil I_1\right\rceil=2

e
\implies\left\lfloor I_2\right\rfloor=-1

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So the given equation reduces to

\displaystyle\sum_{k=-1}^2\frac{\mathrm d}{\mathrm dx}x^{k+2}=1-4!
\dfrac{\mathrm dx}{\mathrm dx}+\dfrac{\mathrm dx^2}{\mathrm dx}+\dfrac{\mathrm dx^3}{\mathrm dx}+\dfrac{\mathrm dx^4}{\mathrm dx}=-23
4x^3+3x^2+2x+24=0

a fairly standard cubic. Incidentally, when x=-2, the LHS reduces to 0, so x+2 is a factor of the cubic. You can find the remaining two solutions easily with the quadratic formula.
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