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natka813 [3]
3 years ago
15

I’m confused need help please

Mathematics
2 answers:
nataly862011 [7]3 years ago
6 0
The answer is 8. Hope this helps!
IrinaK [193]3 years ago
5 0

Answer: The answer is 8

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Which statement correctly describes the expression (-60)(-5)?
Elina [12.6K]
It would be b. If two numbers are negative and your multiplying them, it would be positive!
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3 years ago
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PLEASE HELP
Rama09 [41]
<span>image ​ A′B′C′D′ is 5 times bigger than pre-image ABCD

scale factor = 5</span>
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Kim loves to read. She reads at least one book every week. On Monday, Kim read 1/ 4 of her new book. On Tuesday, she read 1/ 5 o
mixer [17]

Answer:

Step-by-step explanation:

Respectively we will say the book has One thousand pages (1000) . Now we find 1/4 of a 1000 which is 250 , then we find 1/5 of a 1000 which is 200. Now we add them together which is 250+200=450 . 450 / 1000 = 9/20 which is about a half

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3 years ago
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Given f: ℝ → ℝ and : ℝ → ℝ , for the following, find f(g(x)) and g(f(x)), and state the domain.
horrorfan [7]

Answer:

Remember, (f\circ g)(x)=f(g(x)) and the range of g must be in the domain of f.

a)

f(g(x))=f(x-1)=(x-1)^2-(x-1)=x^2-2x+1-x+1=x^2-3x+2

g(f(x))=g(x^2-x)=(x^2-x)-1=x^2-x-1

The domain of f(g(x)) and g(f(x)) is the set of reals.

b)

f(g(x))=f(\sqrt{x}-2)=(\sqrt{x}-2)^2-x=\sqrt{x}^2-2*2*\sqrt{x}+2^2-x=-4\sqrt{x}+4

g(f(x))=g(x^2-x)=\sqrt{x^2-x}-2

The domain of f(g(x)) is the set of nonnegative reals and the domain of g(f(x)) is the set of number such that x^2-x\geq 0

c)

f(g(x))=f(\frac{1}{x-1})=(\frac{1}{x-1})^2=\frac{1}{(x-1)^2}

g(f(x))=g(x^2)=\frac{1}{x^2-1}

The domain of f(g(x)) is the set of reals except the 1 and the domain of g(f(x)) is the set of reals except the 1 and -1

d)

f(g(x))=f(\frac{1}{x-1})=\frac{1}{(\frac{1}{x-1}-1)}=\frac{1}{\frac{2-x}{x-1}}=\frac{x-1}{2-x}

g(f(x))=g(\frac{1}{x+2})=\frac{1}{(\frac{1}{x+2}-1)}=\frac{1}{\frac{-x-1}{x+2}}=\frac{x+2}{-x-1}

The domain of f(g(x)) is the set of reals except 2, and the domain of g(f(x)) is the set of reals except -1.

e)

f(g(x))=f(log(2(x+3)))=f(log(2x+6))=log(2x+6)-1

g(f(x))=g(x-1)=log(2(x-1)+6)=log(2x+4)

The domain of f(g(x)) is the set of nonnegative reals except -3. The domain of g(f(x)) is the set of nonnegative reals except -2.

3 0
3 years ago
Help Meeeeee!!<br><br> PLEASE
fiasKO [112]

Answer:

3/4 (A)

Explanation:

think PEMDAS for the "numerator" of the equation

ill work this out how i would.

3+2=5

5^{2}= 25

50+25=75

75/100=3/4

5 0
3 years ago
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