Answer:
The correct answer is - both act only between non-atomic particles.
Explanation:
The decreasing order of their relative strength is - the strong force, electromagnetism, weak force, gravity.
so, A would be here = gravity
B would be = weak force
C would be = strong force
The weak and strong forces both are fundamental forces that act on sub-atomic particles only such as quarks.
The formula unit for Li and O is —————-> Li2O
Answer:
This question sadly does not make much sense, please rephrase it.
<span>Same answer, different setup. We know that the sum of the oxidation numbers is zero for a compound and the ionic charge for a polyatomic ion, and we know that sulfite ion is -2.
Create an algebraic equation by multiplying the subscripts times the oxidation number of a single element.
+x -6 = -2
+x -2
S O3
Solve for x
x = +4</span>
Answer: The mass percentage of
is 5.86%
Explanation:
To calculate the mass percentage of
in the sample it is necessary to know the mass of the solute (
in this case), and the mass of the solution (pesticide sample, whose mass is explicit in the letter of the problem).
To calculate the mass of the solute, we must take the mass of the
precipitate. We can establish a relation between the mass of
and
using the stoichiometry of the compounds:

Since for every mole of Tl in
there are two moles of Tl in
, we have:

Using the molar mass of
we have:

Finally, we can use the mass percentage formula:
