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nasty-shy [4]
3 years ago
7

Balance the following skeleton reaction and identify the oxidizing and reducing agents: Include the states of all reactants and

products in your balanced equation. You do not need to include the states with the identities of the oxidizing and reducing agents.
CrO_4^2- (aq) + N_2O(g) rightarrow Cr^3+ (aq) + NO(g) [acidic]
The oxidizing agent is:_______.
The reducing agent is:_______.
Chemistry
1 answer:
N76 [4]3 years ago
8 0

Answer:

Oxidizing agent - CrO4^2-

Reducing agent- N2O

Explanation:

Let us look at the equation closely;

CrO4^2- (aq) + 3N2O(g) ------------> Cr^3+ (aq) + 3NO(g) [acidic]

The reduction half equation is;

CrO4^2- (aq) + 3e -------->Cr^3+ (aq)

Oxidation half equation is;

3N2O(g) ------>3 NO(g) +3 e

Note that the oxidizing agent participates in the reduction half equation while the reducing agent participates in the oxidation half equation as seen above.

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The density of a sample of F2(g) is 1.559 g/L. If the gas is held at 755 torr, calculate the temperature.
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Answer:

The temperature is 590,10 K

Explanation:

As stated, we understand that there is one mole of F2, which is equivalent to 37.9968x2 grams = 75.936 grams. The unit of Torr is converted to atm, 1 Torr = 0.0013 atm, and with the data of grams it is converted into volume through density:

density = m / v ---> v = m / density = 75,936 g / 1,559 g / l = 48, 708 l

Exactly the formula PV = nRT

n = number of moles (according to what is interpreted in the sentence is 1 mole)

P = pressure 755 Torr (converted to atm 755Torr / 0.0013 atm / Torr = 0.99344 atm)

R = value constant 0.082 l x atm / K x mol

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0.99344 x 48, 708 l = 1 mol x 0.082 l x atm / K x mol x X

X = 0.99344 x 48, 708 l / 1 mol x 0.082 l x atm / K x mol

X = 590, 10 K

The temperature is 590.10 K

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