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Crazy boy [7]
2 years ago
6

How many p-orbitals are occupied in a Ar atom?

Chemistry
2 answers:
adell [148]2 years ago
8 0

Explanation:

Quantum mechanics stipulates that for each energy level, the p sub shell contains 3 orbitals, px, py, and pz. These orbitals are oriented in alignment with x, y, and axis.

Orlov [11]2 years ago
6 0

Answer:

6

Explanation:

p orbital can hold up to six electron. Argon electron configuration will be 1s²2s²2p⁶3s²3p⁶

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Please help me I need help with this questions I’m very confused fused as to what the answer is please
zepelin [54]
Answer: This was because the experiment showed that a substance could emit radiation even while it was not exposed to light.
3 0
3 years ago
What are three forms of the element carbon?
german

Answer:

There are at least eight forms of carbon: amorphous, graphite, diamond, fullerenes, aggregated diamond nanorods, carbon nanofoam, glassy carbon, and linear acetylenic carbon.

Explanation:

3 0
3 years ago
a chemistry teacher adds 50.0 ml of 1.50 m h2so4 solution to 200 ml of water. What is the concentration of the final solution?
nevsk [136]

Answer:0.300M

Explanation:1) Data:

a) Initial solution

M = 1.50M

V = 50.0 ml = 0.050 l

b) Solvent added = 200 ml = 0.200 l

2) Formula:

Molarity: M = moles of solute / volume of solution is liters

3) Solution:

a) initial solution:

Clearing moles from the molarity formula: moles = M × V

moles of H₂SO₄ = M × V = 1.5M × 0.050 l = 0.075 mol

b) final solution:

i) Volumen of solution = 0.050 l + 0.200l = 0.250l

ii) M = 0.075 mol / 0.250 l = 0.300M ← answeer

5 0
2 years ago
Which would be a good source to find weather information about your town from last month?
VLD [36.1K]

Answer:

a reference book about weather

Explanation:

6 0
3 years ago
Using the molarity equation, calculate how many grams of salt you need in order to make 80ml of a 2M solution (MW = 58.44g/mole)
ollegr [7]

Answer:

9.35g

Explanation:

The molarity equation establishes that:

\textrm{molarity}=\frac{\textrm{moles  of solute}}{\textrm{liters of solution}}

So, we have information about molarity (2M) and volume (80 ml=0.08 l), with that, we can find the moles of solute:

\textrm{moles of solute}=\textrm{molarity}*\textrm{liters of solution}

\textrm{moles of solute}= 0.08 \textrm{ l} *2\textrm{ M} = 0.16 \textrm{ mol}

The  mathematical equation that establishes the relationship between molar weight, mass and moles is:

\textrm{molar weight}= \frac{\textrm{mass}}{\textrm{moles}}

\textrm{MW}= \frac{\textrm{m}}{\textrm{n}}

We have MW (58.44g/mole) and n (0.16 mol), and we need to find m (grams of salt needed) to solve the problem:

\textrm{m} = \textrm{MW * n}= 58.44\frac{\textrm{g}}{\textrm{mol}} * 0.16 \textrm{ mol} = 9.35 \textrm{ g}

8 0
3 years ago
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