Answer is: empirical formula for compound is C₂H₆O.
m(CO₂) = 1,6003 g.
n(CO₂) = m(CO₂) ÷ M(CO₂).
n(CO₂) = 1,6003 g ÷ 44 g/mol.
n(CO₂) = 0,0364 mol.
n(CO₂) = n(C).
m(C) = 0,0364 mol · 12 g/mol = 0,4368 g.
m(H₂O) = 0,9827 g.
n(H₂O) = 0,9827 g ÷ 18 g/mol.
n(H₂O) = 0,0546 mol.
n(H) = 2 · n(H₂O) = 0,1092 mol.
m(H) = 0,1092 mol · 1 g/mol = 0,1092 g.
m(O) = 0,8376 g - 0,4368 g - 0,1092 g = 0,2916 g.
n(O) = 0,2916 g ÷ 16 g/mol = 0,0182 mol.
n(C) : n(H) : n(O) = 0,0364 mol : 0,1092 mol : 0,0182 mol.
n(C) : n(H) : n(O) = 2 : 6 : 1.
You need to have 8 electrons to fill an atom and to fill bond the pairs need to equal 8
Answer:
True
Explanation:
It only becomes a law when someone has proved it, or else it's just a theory.
Answer:
<em>The parent isotope in the given elements is Radium 226.
</em>
Explanation:
The two elements given in the question are radioactive elements radon and Helium which are formed after an Alpha decay happens in the radium 226 to form Radon 222.
Radon has many isotopes out of which here radon 222 is formed which is a noble gas that is odourless colourless but Radioactive. Again in this reaction helium is formed which is again a noble gas and very light in weight.
Answer:
The answer to your question is: [H+] = 10⁻¹²
Explanation:
Remember that pH = -log [H+], then, in this exercise we need to calculate the pH of the substances and compare the results, the one which the higher value will be the strongest base.
a) [H+] = 10^-9 pH = -log[10⁻⁹] = 8
b) [H+] = 10^-11 pH = -log[10⁻¹¹] = 10
c) [H+] = 10^-10 pH = -log[10⁻¹⁰] = 9
d) [H+] = 10^-12 pH = -log[10⁻¹²] = 11 This is the strongest base
