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ratelena [41]
3 years ago
10

If a compound begins with a metal, it most likely is a _______ compound

Chemistry
1 answer:
Bess [88]3 years ago
8 0

Answer:

Metallic compound

Explanation:

Metallic compound -

A metallic compound refers to the species having at least one metal, is known  as a metallic compound.

In general a metallic compound consists of two ions, a positive ion or the cation, is is basically a metal, and,

a negative ion or an anion, which is a non - metal.

Hence, from the given statement of the question,

The correct answer is - metallic compound.  

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2 only is a pretty accurate answer the others dont make sense  to me.

Explanation:

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3 years ago
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Which of the following elements is the most reactive? potassium, lithium sodium, or rubidium
Alex17521 [72]

Answer:

Potassium

Explanation:

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2 years ago
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If you had a glacier and an ice cube, how would the melting points of both differ?​
Dima020 [189]

Answer:

Due to how big the glacier is you would need more heat to melt it and since the ice cube is smaller a small amount of heat would melt it

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8 0
3 years ago
What is the molecular formula for a compound that is 44.87% potassium, 36.7%
Phoenix [80]

Answer:

Molecular formula: S4K8O16  empirical formula: SK2O4

Explanation:

First we find the moles of each by first finding grams (using the percent) and then using stoichiometry to convert into moles:

Sulfur: 696 *.18 = 125.28grams S* \frac{1 mole S}{32.065 g S} = 3.907 moles S

Potassium: 696 *.4487 = 312.2952 *\frac{1 mole K}{39.08 g K}= 7.99117 mole K

Oxygen: 696 * .367 = 255.432 * \frac{1 mol O}{16g O} = 15.9654 mole O

Then we divide each value by the atom with the smallest number of moles to find the mole ratio:

3.907/3.907= 1

7.99117 mole K/ 3.907= 2.043

15.9654 mole O/ 3.907= 4.08

The empirical formula is SK2O4

To find the molecular formula, we divide the mass given (696) by the mass of the empirical formula (174.22) to get 4. We then divide each atom by 4.

Molecular formula: S4K8O16

5 0
3 years ago
A 5.024 mg sample of an unknown organic molecule containing carbon, hydrogen, and nitrogen only was burned and yielded 13.90 mg
Dafna1 [17]

Answer:

C8H17N

Explanation:

Mass of the unknown compound = 5.024 mg

Mass of CO2 = 13.90 mg

Mass of H2O = 6.048 mg

Next, we shall determine the mass of carbon, hydrogen and nitrogen present in the compound. This is illustrated below:

For carbon, C:

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of C = 12/44 x 13.90 = 3.791 mg

For hydrogen, H:

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H = 2/18 x 6.048 = 0.672 mg

For nitrogen, N:

Mass N = mass of unknown – (mass of C + mass of H)

Mass of N = 5.024 – (3.791 + 0.672)

Mass of N = 0.561 mg

Now, we can obtain the empirical formula for the compound as follow:

C = 3.791 mg

H = 0.672 mg

N = 0.561 mg

Divide each by their molar mass

C = 3.791 / 12 = 0.316

H = 0.672 / 1 = 0.672

N = 0.561 / 14 = 0.040

Divide by the smallest

C = 0.316 / 0.04 = 8

H = 0.672 / 0.04 = 17

N = 0.040 / 0.04 = 1

Therefore, the empirical formula for the compound is C8H17N

8 0
3 years ago
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