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3 years ago

If a compound begins with a metal, it most likely is a _______ compound

Chemistry

1 answer:

Bess [88]3 years ago

8 0

Answer:

Metallic compound

Explanation:

Metallic compound -

A metallic compound refers to the species having at least one metal, is known as a metallic compound.

In general a metallic compound consists of two ions, a positive ion or the cation, is is basically a metal, and,

a negative ion or an anion, which is a non - metal.

Hence, from the given statement of the question,

The correct answer is - metallic compound.

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How would one convert 125 lb to kilograms (1 oz = 28 g)?

scZoUnD [109]

Answer:

these answer choices are extremely confusing to read lol.

so the answer is 125lb x 16oz/1lb x 28g/1oz x 1kg/1000g

6 0

3 years ago

A student makes a compound of sulfur and oxygen. She uses 5.00 g of sulfur and 4.99 g of oxygen, and all of the elemental substa

victus00 [196]

First, we apply the law of conservation of mass which states that the total mass in a system remains constant.
Therefore, there must be 5.00 g of sulfur and 4.99 g of oxygen in the product. Now, we determine the mass percentage using:

Mass % = (mass of sulfur x 100) / total mass of compound

Mass % = (5 * 100) / (5 + 4.99)

Mass % = 50.05%

The product contains 50.05% sulfur by mass.

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4 years ago

Observe the concentrations of the hydronium ions(H3O+), hydroxide ions(OH-), and water (H2O) in the “Water Components” chart on

tia_tia [17]

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6 0

3 years ago

For the reaction 2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g). E∘=0.483 V what is the cell potential at 25 ∘C if the concentrations are [

sveta [45]

Explanation:

The given data is as follows.

$E^{o}$ = 0.483, $[Co^{3+}]$ = 0.173 M,

$[Co^{2+}]$ = 0.433 M, $[Cl^{-}]$ = 0.306 M,

$P_{Cl_{2}}$ = 9.0 atm

According to the ideal gas equation, PV = nRT

or, P = $\frac{n}{V}RT$

Also, we know that

Density = $\frac{mass}{volume}$

So, P = MRT

and, M = $\frac{P}{RT}$

= $\frac{9.0 atm}{0.0820 L atm/mol K \times 298 K}$

= $\frac{9.0}{24.436}$

= 0.368 mol/L

Now, we will calculate the cell potential as follows.

E = $E^{o} - \frac{0.0591}{n} log \frac{[Co^{2+}]^{2}[Cl_{2}]}{[Co^{3+}][Cl^{-}]^{2}}$

= $0.483 - \frac{0.0591}{2} log \frac{(0.433)^{2}(0.368)}{(0.173)(0.306)^{2}}$

= $0.483 - 0.02955 log \frac{0.0689}{0.0162}$

= $0.483 - 0.02955 \times 0.628$

= 0.483 - 0.0185

= 0.4645 V

Thus, we can conclude that the cell potential of given cell at $25^{o}C$ is 0.4645 V.

4 0

4 years ago

Help please. 15.0 moles of gas are in a 3.00L tank at 23.4∘C . Calculate the difference in pressure between methane and an ideal

CaHeK987 [17]

Using PV=nRT or the ideal gas equation, we substitute n= 15.0 moles of gas, V= 3.00L, R equal to 0.0821 L atm/ mol K and T= 296.55 K and get P equal to 121.73 atm. The Van der waals equation is (P + n^2a/V^2)*(V-nb) = nRT. Substituting a=2.300L2⋅atm/mol2 and b=0.0430 L/mol, P is equal to 97.57 atm. The difference is <span>121.73 atm- 97.57 atm equal to 24.16 atm.</span>

3 0

3 years ago