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kenny6666 [7]
3 years ago
11

I need A and b please First to get it gets brainiest

Mathematics
1 answer:
slega [8]3 years ago
8 0

Answer:

B)

Step-by-step explanation:

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Which ordered pair (a, b) is a solution to the given system of linear equations? -2a+3b=14
Stels [109]

Answer:

The solution of the system is the ordered pair (-13,-4)

Step-by-step explanation:

we have

-2a+3b=14 -----> equation A

a-4b=3 ----> equation B

Solve the system by elimination

Multiply by 2 both sides equation B

2(a-4b)=2(3)

2a-8b=6 ----> equation C

Adds equation A and equation C

-2a+3b=14\\2a-8b=6\\-------\\3b-8b=14+6\\-5b=20\\b=-4

<em>Find the value of a</em>

substitute the value of b in any equation (i take equation B)

a-4(-4)=3

a+16=3

a=-13

therefore

The solution of the system is the ordered pair (-13,-4)

6 0
3 years ago
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Fundamental theorem of calculus<br> <img src="https://tex.z-dn.net/?f=g%28s%29%3D%5Cint%5Climits%5Es_6%20%7B%28t-t%5E4%29%5E6%7D
mr_godi [17]

Answer:

\displaystyle g'(s) = (s-s^4)^6

Step-by-step explanation:

The Fundamental Theorem of Calculus states that:
\displaystyle \frac{d}{dx}\left[ \int_a^x f(t)\, dt  \right] = f(x)

Where <em>a</em> is some constant.

We can let:
\displaystyle g(t) = (t-t^4)^6

By substitution:

\displaystyle g(s) = \int_6^s g(t)\, dt

Taking the derivative of both sides results in:
\displaystyle g'(s) = \frac{d}{ds}\left[ \int_6^s g(t)\, dt\right]

Hence, by the Fundamental Theorem:

\displaystyle \begin{aligned} g'(s) & = g(s) \\ \\  & = (s-s^4)^6\end{aligned}

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2 years ago
The qestion Is the picture below extra point's​
LenKa [72]

Answer:

D) y=0.75x+1

Step-by-step explanation:

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3 years ago
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At what point do the lines y = 6x – 18 and<br> y=8x – 32 intersect?
anzhelika [568]

Answer:

(7, 24)

Step-by-step explanation:

Solve the system:

6x - 18 = 8x - 32

2x = 14

x = 7

y = 6(7) - 18

y = 24

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3 years ago
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