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3 years ago

Loan Term (Months)

Mathematics

1 answer:

kodGreya [7K]3 years ago

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1000 tickets were bought at a concert. the amount needed to buy a children’s ticket was $4.50 and the amount needed for an adult

Sholpan [36]

Answer:

The number of children's tickets bought was 300 and the number of adult tickets bought was 700

Step-by-step explanation:

Let

x ----> the number of children's tickets bought

y ----> the number of adult tickets bought

we know that

$x+y=1,000$

$x=1,000-y$ -----> equation A

$4.50x+8.50y=7,300$ -----> equation B

Solve the system by substitution

substitute equation A in equation B

$4.50(1,000-y)+8.50y=7,300$

solve for x

$4,500-4.50y+8.50y=7,300$

$4y=7,300-4,500$

$4y=2,800$

$y=700$

<em>Find the value of x</em>

$x=1,000-700=300$

therefore

The number of children's tickets bought was 300 and the number of adult tickets bought was 700

6 0

3 years ago

Sara is building a fence that will be 7 miles long when it is completed. Sara has finished building 2/3 of the fence. What is th

Butoxors [25]

Answer:

7/3 ft

Step-by-step explanation:

Given data

Lenght of fence= 7 miles

Amount completed= 2/3 of the total length

let us find the amount completed already = 2/3*7= 14/3 miles

Hence the length of fence remaining for completion is

=7- 14/3

=21-14/3

=7/3

Hence the amount in length undon is 7/3 ft

3 0

3 years ago

A custodian pours 3/8 gallon of cleaning solution equally into nine pails find the volume of the solution and two of these pails

kaheart [24]

3/72=1/24
You divide 3/8 with 9 then simplify

7 0

3 years ago

Jojo is reading a novel that is broken into three major parts. The number of pages in Part One is 2/5 of the novel's total numbe

Anit [1.1K]

Answer:

3/10

Step-by-step explanation:

Part I: 2/5 = 4/10

Part II: 3/4(2/5) = 6/20 or 3/10

Part III: 10/10 - (4/10 + 3/10) = 3/10

4 0

3 years ago

I need to find the missing numbers

const2013 [10]

Answer:

b11 = -14

b12 = 9

b13 = 8

Step-by-step explanation:

* Lets revise some notes to solve the problem

- Any matrix has a dimension m × n, where m is the number of rows

and n the number of columns

- We can add matrices with same dimensions

* Now lets solve the problem

∵ $B+\left[\begin{array}{ccc}15&-7&4\\0&1&2\end{array}\right]=\left[\begin{array}{ccc}1&2&12\\4&0&2\end{array}\right]$

- Let $B=\left[\begin{array}{ccc}b11&b12&b13\\b21&b22&b23\end{array}\right]$

∴ $\left[\begin{array}{ccc}b11&b12&b13\\b21&b22&b23\end{array}\right]+\left[\begin{array}{ccc}15&-7&4\\0&1&2\end{array}\right]=\left[\begin{array}{ccc}1&2&12\\4&0&2\end{array}\right]$

- Lets add and find the missing

* Lets start with the first rows

∵ b11 + 15 = 1 ⇒ subtract 15 from both sides

∴ b11 = -14

∵ b12 + -7 = 2 ⇒ add 7 to both sides

∴ b12 = 9

∵ b13 + 4 = 12 ⇒ subtract 4 from both sides

∴ b13 = 8

* Now lets start with the second rows

∵ b21 + 0 = 4

∴ b21 = 4 ⇒ given

∵ b22 + 1 = 0 ⇒ subtract 1 from both sides

∴ b22 = -1 ⇒ given

∵ b23 + 2 = 2 ⇒ subtract 2 from both sides

∴ b23 = 0 ⇒ given

5 0

3 years ago