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guapka [62]
3 years ago
8

Can someone help me... pls show work:((((

Mathematics
1 answer:
densk [106]3 years ago
4 0

Answer:

h^2=a^2+o^2

h^2= 7^*7^2

h^2=49+49

h^2=98

h=√98

h=9.899 or 9.9

I used the Pythagoras theorem

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Count the number of 5-digit numbers (in the decimal system; integers from 10000 to 99999) which are not divisible by 11.
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Answer:

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Step-by-step explanation:

We have to find the total numbers which are not divisible by 11 from 10000 to 99999

Total number from 10000 to 99999 = 99999-10000+1=90000

Just after 10000 the number which is divisible by 11 is 10010

And just below 99999 the number which is divisible by 11 is 99990

Using AP formula

T_N=a+(n-1)d, here a is first term, d is common difference and n is number of terms

So 99990=10010+(n-1)11

n-1 = 8180

n= 8181

So total number which is not divisible by 11 = 90000-8181 = 81819

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