3 years ago

I already did number 1 but can someone help me with number 2

Mathematics

1 answer:

hammer [34]3 years ago

4 0

Answer:

17×17 is 289 therefore her calculation is correct

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I need help with 10,11,12,13 plz it's due tomorrow

tangare [24]

10. GCF is 3

11. GCF is 4

12. GCF is 16

13. That the numbers are prime

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3 years ago

Select the statements that are true for the graph of y=(x+2)^2+4

likoan [24]

Alrigty

in form
$y=a(x-h)^2+k$
the vertex is (h,k)
the constant, a, deterimines the size and direction
if a>0, then the parabola opens up and the vertex is the minimum
if a<0 then the parabola opens down and the vertex is the maximum

so we are given
$y=1(x-(-2))^2+4$
1>0 so it opens up
vertex is (-2,4)
the vertex is a minimum

the vertex is (-2,4) and the graph has a minimum

3 0

3 years ago

Read 2 more answers

A landscape supply business $30 to deliver mulch. The cost of the mulch is $23 per cubic yard. Write and solve a linear equation

Andru [333]

The answer is $209 bye lol

4 0

3 years ago

(b) If a series follows geometric progression, show that the ratio of the sum of term to the sum from (n+1) term to (2n) term is

Nadusha1986 [10]

Proof with explanation:

We know that the sum of first 'n' terms of a Geometric progression is given by

$S_{n}=\frac{a(1-r^{n})}{1-r}$

where

a = first term of G.P

r is the common ratio

'n' is the number of terms

Thus the sum of 'n' terms is

$S_{n}=\frac{a(1-r^{n})}{1-r}$

Now the sum of first '2n' terms is

$S_{2n}=\frac{a(1-r^{2n})}{1-r}$

Now the sum of terms from $(n+1)^{th}$ to $(2n)^{th}$ term is $S_{2n}-S_{n}$

Thus the ratio becomes

$\frac{S_{n}}{S_{2n}-S_{n}}\\\\=\frac{\frac{a(1-r^{n})}{1-r}}{\frac{a(1-r^{2n})}{1-r}-\frac{a(1-r^{n})}{1-r}}\\\\=\frac{1-r^{n}}{r^{n}-r^{2n}}\\\\=\frac{1-r^{n}}{r^{n}(1-r^{n})}\\\\=\frac{1}{r^{n}}$

5 0

3 years ago

3x+2>2 and 3x less than or equal to 6

Y_Kistochka [10]

3x + 2 > 2
3x > 2 - 2
3x > 0
x > 0

3x < = 6
x < = 6

0 < x < = 6

4 0

3 years ago