Write in the correct coefficients for the balanced equation: Na + Cl2 → NaCl

Chemistry

2 answers:

Mkey [24]3 years ago

7 0

Answer:

Na+Cl2-----NaCl

Explanation:

it's the chemical formula of common salt.

Westkost [7]3 years ago

5 0

Answer:

2Na + Cl2 → 2NaCl

Explanation:

Na + Cl2 → NaCl

We have two chlorines on the left but only one on the right so it needs to be balanced.

If we put a 2 in front of NaCl we now have 2 chlorines on both sides but now 2 sodiums on the left and one on the right

Add another 2 in front of Na to get the full balanced equation

2Na + Cl2 → 2NaCl

You might be interested in

What type of clothing would you need to wear if you could visit the mesosphere

Keith_Richards [23]

It is very cold there 90 degrees celsius so dress very warm!

5 0

3 years ago

1. In an equilibrium experiment, acetic acid (which is a weak acid) is mixed with sodium acetate (a soluble salt), with methyl o

koban [17]

Explanation:

It is known that acetic acid is a weak acid. It's equilibrium of dissociation will be represented as follows.

$CH_{3}COOH(aq) + H_{2}O(l) \rightleftharpoons CH_{3}COO^{-}(aq) + H_{3}O^{+}(aq)$

On the other hand, sodium acetate ( $CH_{3}COONa$ ) is a salt of weak acid, that is, $CH_{3}COOH$ and strong base, that is, NaOH. Therefore, aqueous solution of sodium acetate will be basic in nature.

Since, acetic acid is a weak acid but still it is an acid. So, when methyl orange is added in a solution of acetic acid then it given a reddish-orange color because of its acidity.

When sodium acetate is mixed into this solution then it will dissociate as follows.

$CH_{3}COO^{-}Na^{+}(aq) \rightleftharpoons CH_{3}COO^{-}(aq) + Na^{+}(aq)$

As both solutions are liberating acetate ion upon dissociation. Hence, it is the common ion.

So, when more acetate ions will increase from dissociation of sodium acetate the according to Le Chatelier's principle the equilibrium will shift on left side.

As a result, there will be decrease in the concentration of hydronium ions. As a result, there will be increase in the pH of the system.

Hence, color of methyl orange will change from reddish orange to yellow. This shift in equilibrium is due to the common ion which is $CH_{3}COO^{-}$ ion.