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3 years ago

Write in the correct coefficients for the balanced equation: Na + Cl2 → NaCl

Chemistry

2 answers:

Mkey [24]3 years ago

7 0

Answer:

Na+Cl2-----NaCl

Explanation:

it's the chemical formula of common salt.

Westkost [7]3 years ago

5 0

Answer:

2Na + Cl2 → 2NaCl

Explanation:

Na + Cl2 → NaCl

We have two chlorines on the left but only one on the right so it needs to be balanced.

If we put a 2 in front of NaCl we now have 2 chlorines on both sides but now 2 sodiums on the left and one on the right

Add another 2 in front of Na to get the full balanced equation

2Na + Cl2 → 2NaCl

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A thermometer reads an outside air temperature of 35°c. What is the temperature in degrees Fahrenheit

Hoochie [10]

35°c is equal to 95°f

To do this multiply 35 and 1.8

35 x 1.8=63

Now add 32

Resulting in the answer 95

(The equation for to solve for c and f is c1.8+32=f

3 0

3 years ago

Sodium sulfate is slowly added to a solution containing 0.0500 M Ca 2 + ( aq ) and 0.0390 M Ag + ( aq ) . What will be the conce

levacccp [35]

The given question is incomplete. The complete question is as follows.

Sodium sulfate is slowly added to a solution containing 0.0500 M $Ca^{2+}(aq)$ and 0.0390 M $Ag^{+}(aq)$ . What will be the concentration of $Ca^{2+}$ (aq) when $Ag_{2}SO_{4}(s)$ begins to precipitate? What percentage of the $Ca^{2+}(aq)$ can be separated from the Ag(aq) by selective precipitation?

Explanation:

The given reaction is as follows.

$Ag_{2}SO_{4} \rightleftharpoons 2Ag^{+} + SO^{2-}_{4}$

$[Ag^{+}]$ = 0.0390 M

When $Ag_{2}SO_{4}$ precipitates then expression for $K_{sp}$ will be as follows.

$K_{sp} = [Ag^{+}]^{2}[SO^{2-}_{4}]$

$1.20 \times 10^{-5} = (0.0390)^{2} \times [SO^{2-}_{4}]$

$[SO^{2-}_{4}]$ = 0.00788 M

Now, equation for dissociation of calcium sulfate is as follows.

$CaSO_{4} \rightleftharpoons Ca^{2+} + SO^{2-}_{4}$

$K_{sp} = [Ca^{2+}][SO^{2-}_{4}]$

$4.93 \times 10^{-5} = [Ca^{2+}] \times 0.00788$

$[Ca^{2+}]$ = 0.00625 M

Now, we will calculate the percentage of $Ca^{2+}$ remaining in the solution as follows.

$\frac{0.00625}{0.05} \times 100$

= 12.5%

And, the percentage of $Ca^{2+}$ that can be separated is as follows.

100 - 12.5

= 87.5%

Thus, we can conclude that 87.5% will be the concentration of $Ca^{2+}(aq)$ when $Ag_{2}SO_{4}(s)$ begins to precipitate.

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3 years ago

Please answer this correctly,,, This is a huge part of my grade. And who ever answers correctly will get brainliest!

chubhunter [2.5K]

Answer:

I belive it's the black chair because they were asking which chair experienced the most force in the begining and the black chair had the most force given.

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3 years ago

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