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skelet666 [1.2K]
4 years ago
12

Consider four different samples: aqueous LiBr , molten LiBr , aqueous AgBr , and molten AgBr . Current run through each sample p

roduces one of the following products at the cathode: solid lithium, solid silver, or hydrogen gas. Match each sample to its cathodic product.Math following to Cathoid Products-Solid Lithium, Solid Silver, and Hydrogen GasSamples1. Aqueous LiBr2. Molten LiBr3. Aqueous AgBr4. Molten AgBr
Chemistry
1 answer:
Charra [1.4K]4 years ago
6 0

Answer:

a) Aqueous LiBr = Hydrogen Gas

b) Aqueous AgBr = solid Ag

c) Molten LiBr = solid Li

c) Molten AgBr = Solid Ag

Explanation:

a) Aqueous LiBr

This sample produces Hydrogen gas, because the H+ (conteined in the water) has a reduction potential higher than the Li+ from the salt. Therefore the hydrogen cation will reduce instead of the lithium one and form the gas.

b) Aqueous AgBr

This sample produces Solid Ag, because the Ag+ has a reduction potential higher than the H+ from the water. Therefore the silver cation will reduce instead of the hydrogen one and form the solid.

c) Molten LiBr

In a molten binary salt like LiBr there is only one cation present in the cathod. In this case the Li+, so it will reduce and form solid Li.  

c) Molten AgBr

The same as the item above: there is only one cation present in the cathod. In this case the Ag+, so it will reduce and form solid Ag.  

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Gallium is produced by the electrolysis of a solution obtained by dissolving gallium oxide in concentrated NaOH(aq). Calculate t
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<u>Answer:</u> The mass of gallium produced by the electrolysis is 0.0354 grams.

<u>Explanation:</u>

The equation for the deposition of Ga(s) from Ga(III) solution follows:

Ga^{3+}(aq.)+3e^-\rightarrow Ga(s)

  • To calculate the total charge, we use the equation:

C=I\times t

where,

C = charge

I = current = 0.490 A

t = time required (in seconds) = 50\times 60=300s    (Conversion factor: 1 min = 60 s)

Putting values in above equation, we get:

C=0.490\times 300=147C

  • To calculate the moles of electrons, we use the equation:

\text{Moles of electrons}=\frac{C}{F}

where,

C = charge = 147 C

F = Faradays constant = 96500

\text{Moles of electrons}=\frac{147}{96500}=1.52\times 10^{-3}mol

  • Now, to calculate the moles of gallium, we use the equation:

\text{Moles of Gallium}=\frac{\text{Moles of electrons}}{n}

where,

n = number of electrons transferred = 3

Putting values in above equation, we get:

\text{Moles of Gallium}=\frac{1.52\times 10^{-3}}{3}=5.077\times 10^{-4}mol

  • To calculate the mass of gallium, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of Gallium = 5.077\times 10^{-4}mol

Molar mass of Gallium = 69.72 g/mol

Putting values in above equation, we get:

5.077\times 10^{-4}mol=\frac{\text{Mass of Gallium}}{69.72g/mol}\\\\\text{Mass of Gallium}=0.0354g

Hence, the mass of gallium produced by the electrolysis is 0.0354 grams.

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A gas cylinder contains exactly 1 mole of oxygen gas (O2). How many molecules of oxygen are in the cylinder?
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The number of molecules of oxygen in the cylinder is 6.02×1023 molecules

Data obtained from the question

Number of mole of oxygen = 1 mole

Number of molecule of oxygen =?

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×1023 molecules. This implies that 1 mole of oxygen contains 6.02×1023 molecules.

Since the cylinder contains 1 mole of oxygen, then the number of molecules of oxygen present in the cylinder is 6.02×1023 molecules.

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