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3 years ago

This is due at 12am HELP!!

Chemistry

1 answer:

Lisa [10]3 years ago

4 0

Answer:

I have the same

Explanation:

like I have the same homework as you are u in my class lol?

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Which of the following are correct about nodal planes in molecular orbitals? There may have more than one correct answers. Pictu

azamat

Explanation:

I'll give you a real answer later need points for test questions sorry

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3 years ago

The Lanthanides are often be found below the Periodic Table so it will fit nicely on a textbook page. If they were inserted into

Annette [7]

Answer:

period 6

Explanation:

If the lanthanides were inserted into the periodic table, they would go into periodic 6.

Their atomic number is between 57 - 71 from element lanthanum to lutetium.

The elements in this period are 15 in number.
They are also know as elements in the f-block.

The elements that makes up the series are:

Lanthanum

Cerium

Praseodymium

Neodymium

Promethium

Samarium

Europium

Gadolinium

Terbium

Dysprosium

Holmium

Erbium

Thulium

Ytterbium

Lutetium

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3 years ago

When preparing a buret for use in lab, the buret must always be cleaned thoroughly. prior to being filled with solution, the bur

erastova [34]

It is rinsed one last time with the solution to be measured because if there is water in the burret, then it could alter the results. Slightly, but it is still altering it.

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3 years ago

Identify at least three control variables that could be used with this investigation: What temperature allows for bacterial grow

Over [174]

Answer:

Time allowed for incubation, size of the dish, the amount of light, amount of agar, the type of agar…etc

Explanation:

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3 years ago

Read 2 more answers

At 7 degrees Celsius the volume of gas is 49 liters. At the same pressure its volume is 74 mL at what temperature

Romashka-Z-Leto [24]

Charle's law gives the relationship between volume and temperature of gas.
It states that at constant pressure, volume of gas is directly proportional to temperature of gas.
V/T = k
where V - volume , T - temperature and k- constant
$\frac{V1}{T1} = \frac{V2}{T2}$
parameters for the first instance are on the left side of the equation and parameters for the second instance are on the right side of the equation
T1 - 7 °C + 273 = 280 K
substituting these values in the equation
$\frac{49 mL}{280K} = \frac{74 mL}{T}$
T = 423 K
temperature in Celcius scale - 423 K - 273 = 150 °C

4 0

3 years ago