Answer:
Heat absorbed by water = 3985.26 j
Explanation:
Given data:
Mass of water = 75 g
Initial temperature = 20.0°C
Final temperature = 32.7°C
Specific heat of water = 4.184 j/g.°C
Heat absorbed by water = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 32.7°C - 20°C
ΔT = 12.7 °C
Q = 75 g ×4.184 j/g.°C ×12.7 °C
Q = 3985.26 j
Answer:
Amount of 
produced will be half of its original value.
Explanation:
Balanced reaction: 
According to balanced equation, 1 mol of HCl reacts with 1 mol of NaOH to produce 1 mol of
If amount of reactants (NaOH and HCl) are halved then we can write-
0.5 mol of HCl reacts with 0.5 mol of NaOH to produce 0.5 mol of .
So, it is evident that amount of to be produced will be half if amount of reactants are halved.
Here is the link to the answer:
An exothermic reaction is a type of reaction that dissipates heat as the reaction proceeds. This would mean that in a closed system, when a reaction proceeds and is endothermic, the temperature of the solution or the system would increase so as to maintain the equilibrium with the whole system.
