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labwork [276]
3 years ago
12

figure 2 shows a charged ball of mass m = 1.0 g and charage q = -24*10^-8 c suspended by massless string in the presence of a un

iform electric field E , in this field the ball is in equilibrium at theta = 37 , calculate the magnitude of the electric field E

Physics
1 answer:
Vlad [161]3 years ago
8 0

Answer:

E = 307667  N/C

Explanation:

Since the object's mass is 1 g, then its weight in newtons is 0.001 * 9.8 = 0.0098 N.

This weight should have the same magnitude of the vertical component of the tension T of the string (T * cos(37)) so we can find the magnitude of the tension T via:

0.0098 N = T * cos(37)

then T = 0.0098/cos(37) N = 0.01227 N

Knowing the tension's magnitude, we can find its horizontal component:

T * sin(37) = 0.007384 N

and now we can obtain the value of the electric field since we know the charge of the ball to be: -2.4 * 10^(-8) C:

0.007384 N = E * 2.4 * 10^(-8) C

Then  E = 0.007384/2.4 * 10^(-8)  N/C

E = 307667  N/C

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<h3>Work done by the applied force</h3>

The work done by the applied force is calculated as follows;

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