Bob ran at 5 m/s for 4 seconds and ended up at position 8 m. Where did he start

he amplitude of a lightly damped harmonic oscillator decreases by 3.0% during each cycle.show answer no attempt what percentage

GrogVix [38]

The percentage of mechanical energy of the oscillator lost in each cycle is 5.91 %.

The formula for mechanical energy in an oscillator is given by

E = 1/2 kA²

It is the sum of elastic potential energy and kinetic energy.

Amplitude is nothing but the maximum displacement moved by a point on vibrating body.

It is given that the amplitude A decreases by 3%, then

(E₂ - E₁) / E₁ = [1/2 k (A₂²- A₁²)] /(1/2 k A₁²) = (A₂²- A₁²)/ A₁² = (97² - 100²)/ 100²

⇒ 5.91% of the mechanical energy is lost in each cycle.

To know more about mechanical energy:

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4 0

1 year ago

What substance might impact the formation of volcanic rock?<br><br> marking brainliest!

RoseWind [281]

Answer:

WATER

Explanation:

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3 0

3 years ago

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The volume of gas decreases at constant temperature to 80% of the inital value. How does the pressure value change relative to t

Westkost [7]

Answer:

The pressure value changes 400 % relative to the initial value.

Explanation:

Let suppose that the gas behaves ideally and represents a closed system, that is, a system with no mass interactions so that number of moles is conserved ( $n$ ). Since the variables involved in the isothermal process are pressure ( $P$ ) and volume ( $V$ ). Finally, the process is represented by the following relationship:

$P_{1}\cdot V_{1} = P_{2}\cdot V_{2}$ (1)

Where:

$P_{1}, P_{2}$ - Initial and final pressures.

$V_{1}, V_{2}$ - Initial and final volumes.

If we know that $P_{1} = P_{o}$ , $V_{1} = V_{o}$ and $V_{2} = 0.2\cdot V_{o}$ , then the final pressure of the closed system is:

$P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}} \right)$

$P_{2} = 5\cdot P_{o}$

The pressure value changes 400 % relative to the initial value.

8 0

3 years ago

This type of water occurs as a liquid resource that is dispersed through numerous holes, pores, fractures, and cavities in bodie

777dan777 [17]

Answer:

C

Explanation:

Although this may seem surprising, water beneath the ground is commonplace. Usually groundwater travels slowly and silently beneath the surface, but in some locations it bubbles to the surface at springs. The products of erosion and deposition by groundwater were described in the Erosion and Deposition chapter.

Groundwater is the largest reservoir of liquid fresh water on Earth and is found in aquifers, porous rock and sediment with water in between. Water is attracted to the soil particles and capillary action, which describes how water moves through a porous media, moves water from wet soil to dry areas.

Aquifers are found at different depths. Some are just below the surface and some are found much deeper below the land surface. A region may have more than one aquifer beneath it and even most deserts are above aquifers. The source region for an aquifer beneath a desert is likely to be far from where the aquifer is located; for example, it may be in a mountain area.

The amount of water that is available to enter groundwater in a region is influenced by the local climate, the slope of the land, the type of rock found at the surface, the vegetation cover, land use in the area, and water retention, which is the amount of water that remains in the ground. More water goes into the ground where there is a lot of rain, flat land, porous rock, exposed soil, and where water is not already filling the soil and rock.

The residence time of water in a groundwater aquifer can be from minutes to thousands of years. Groundwater is often called “fossil water” because it has remained in the ground for so long, often since the end of the ice ages.

8 0

3 years ago

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A stone is thrown vertically upward with an initial speed of 24.7 m/s. Neglect air resistance. The speed of the stone when it is

fredd [130]

Answer:

The speed of the stone when it is 4.66 m higher is 236.057 m/s.

Explanation:

Given the initial velocity and vertical distance, we can use the fourth kinematic equation ( $v^{2} =v_{o}^{2}+2ay$ ) to find v final, or the v to the left of the equal sign. We know $v_{o}$ (initial velocity) is 24.7 m/s, y (change in vertical distance) is 4.66 m, and a is another way to write g (acceleration due to gravity), or 9.8 $m/s^{2}$ .

From here you could plug in the values and solve for v final, but to make the solving process simpler, we can simplify the given equation, <em>then </em>plug in the known values.

To isolate v final, we can take the square root of $v^{2}$ and do the same to the right side of the equation. Therefore, we can find v final with: $v_{o} \sqrt{2ay}$ , where v initial is outside of the square root because it squared...

If we plug in the known values to the simplified equation, we get: $v=24.7m/s*\sqrt{2(9.8m/s)(4.66 m)}$

The final answer is 236.057 m/s.

4 0

2 years ago