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Dovator [93]
2 years ago
8

A box has a mass of 6.0 kg. What is its weight on the mars, where the acceleration due to

Physics
1 answer:
Dvinal [7]2 years ago
3 0

Answer:

The weight of the box is 22.38 N.

Explanation:

The weight (W) of the mass is given by:

W = mg

Where:            

m: is the mass of the box = 6.0 kg

g_{m}: is the acceleration due to gravity of mars

Since the acceleration due to the gravity of mars is 0.38 times that on Earth we have:

g_{m} = 0.38g_{E} = 0.38*9.81 m/s^{2} = 3.73 m/s^{2}

Hence, the weight of the mass is:

W = mg = 6.0 kg*3.73 m/s^{2} = 22.38 N

Therefore, the weight of the box is 22.38 N.

I hope it helps you!      

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Which process do single-celled organisms go through to reproduce asexually?
andrezito [222]
The answer is A-Mitosis
7 0
3 years ago
Un proyectil es lanzado horizontalmente desde una altura de 12 metro con una velocidad de 80 m/sg. a.Calcular el tiempo de vuelo
Naily [24]

Answer:

t= 1,56 s ,   x= 124,8 m , v = (80 i^ - 15,288 j ) m/s

Explanation:

Este es un ejercicio de lanzamiento proyectiles, comencemos por encontrar el tiempo que tarda en llegar al piso

        y = y₀ + v_{oy} t – ½ g t²

en este caso la altura inicial es y₀= 12 m y llega a y=0 , como es lanzado horizontalmente la velocidad vertical es cero (v_{oy}=0)

       0 = y₀ – ½ g t²

       t= √ (2 y₀/g)

calculemos

       t= √ ( 2 12 / 9,8)

       t= 1,56 s

El alcance del proyectil es la distancia horizontal recorrida  

        x = v₀ₓ t

        x = 80 1,56

        x= 124,8 m

La velocidad de impacto cuando toca el suelo

        vx = v₀ₓ = 80 ms

        v_{y} = v_{oy} – gt

        v_{y} = - 9,8 1,56

        v_{y} = - 15,288 m/s

la velocidad es

       v = (80 i^ - 15,288 j ) m/s

Traducttion  

This is a projectile launching exercise, let's start by finding the time it takes to reach the ground

        y = y₀ + v_{oy} t - ½ g t²

in this case the initial height is i = 12 m and it reaches y = 0, as it is thrown horizontally the vertical speed is zero (v_{oy} = 0)

       0 =y₀I - ½ g t²

       t = √ (2y₀ / g)

let's calculate

       t = √ (2 12 / 9.8)

       t = 1.56 s

Projectile range is the horizontal distance traveled

        x = v₀ₓ t

        x = 80 1.56

        x = 124.8 m

Impact speed when it hits the ground

        vₓ = v₀ₓ = 80 ms

        v_{y} = v_{oy} - gt

        v_{y} = - 9.8 1.56

        v_{y} = - 15,288 m / s

the speed is

       v = (80 i ^ - 15,288 j) m / s

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3 years ago
Which of these is a mixture?
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Answer:

Air is a mixture.

Explanation:

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Carbon dioxide is a pure substance, not a mixture.

Carbon is another pure substance, it cannot be separated into other substances.

Oxygen is just oxygen, it does not contain any other substance.

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The force applied when using a simple machine ??
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Answer : I hope this helps !

The Effort Force is the force applied to a machine. Work input is the work done on a machine. The work input of a machine is equal to the effort force times the distance over which the effort force is exerted.
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Other quanto
Alex73 [517]

I'm not sure what you were trying to put here

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