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Hoochie [10]
3 years ago
13

uniform solid sphere of radius R rotates about a diameter with an angular speed 536 radians/second. The sphere then collapses un

der the action of internal forces to a final radius R/2. What is the final angular speed of the sphere in radians/second?
Physics
2 answers:
weeeeeb [17]3 years ago
4 0

Answer:

2144 rad/s

Explanation:

R1 = R

ω1 = 536 rad/s

R2 = R/2

ω2 = ?

Mass is M

By use of angular momentum remains constant if no external force is acting on the body.

I1 ω1 = I2 ω2

The moment of inertia of solid sphere is 12/5 MR^2

So, 2/5 x M R^2 x 536 = 2/5 x M (R/2)^2 x ω2

536 = ω2 / 4

ω2 = 2144 rad/s

Ainat [17]3 years ago
3 0

Answer:

ω₂ = 2144 rad/s

Explanation:

angular  speed =  536 radians/second

as, we all know the moment of inertia of solid sphere

I_{sphere}= \dfrac{2}{5}MR^2

here in the question two radius are given

by using angular momentum conservation

I_1 \omega_1 = I_2 \omega_2

\dfrac{2}{5}MR_1^2 \omega_1 =\dfrac{2}{5}MR_2^2 \omega_2\\R^2\times 536= \dfrac{R^2}{4}\times \omega_2

\omega_2 = 4 \times 536

ω₂ = 2144 rad/s

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The average standard rectangular building brick has a mass of 3.10 kg and dimensions of 225 m x 112 m x 75 m. The gravitational
zzz [600]

Answer:

P=3.61\times 10^{-3}\ Pa

Explanation:

Given that,

Mass of a brick, m = 3.1 kg

The dimensions of the brick 225 m x 112 m x 75 m

We need to find the maximum pressure created by the brick. We know that, the force acting per unit area is called pressure exerted. It is given by the formula as follows :

P=\dfrac{F}{A}

F = mg

A = area with minimum dimensions i.e. 112 m x 75 m

Pressure is maximum when the area is least.

So,

P=\dfrac{mg}{A}\\\\P=\dfrac{3.1\times 9.8}{112\times 75}\\\\P=3.61\times 10^{-3}\ Pa

So, the maximum pressure created by brick is 3.61\times 10^{-3}\ Pa.

5 0
3 years ago
A beam of protons is moving toward a target in a particle accelerator. This beam constitutes a current whose value is. (a) How m
Gelneren [198K]

Answer:

a. 5 × 10¹⁹ protons b. 2.05 × 10⁷ °C

Explanation:

Here is the complete question

A beam of protons is moving toward a target in a particle accelerator. This beam constitutes a current whose value is 0.42 A. (a) How many protons strike the target in 19 seconds? (b) Each proton has a kinetic energy of 6.0 x 10-12 J. Suppose the target is a 17-gram block of metal whose specific heat capacity is 860 J/(kg Co), and all the kinetic energy of the protons goes into heating it up. What is the change in temperature of the block at the end of 19 s?

Solution

a.

i = Q/t = ne/t

n = it/e where i = current = 0.42 A, n = number of protons, e = proton charge = 1.602 × 10⁻¹⁹ C and t = time = 19 s

So n = 0.42 A × 19 s/1.602 × 10⁻¹⁹ C

       = 4.98 × 10¹⁹ protons

       ≅ 5 × 10¹⁹ protons

b

The total kinetic energy of the protons = heat change of target

total kinetic energy of the protons = n × kinetic energy per proton

                                                         = 5 × 10¹⁹ protons × 6.0 × 10⁻¹² J per proton

                                                         = 30 × 10⁷ J

heat change of target = Q = mcΔT ⇒ ΔT = Q/mc where m = mass of block = 17 g = 0.017 kg and c = specific heat capacity = 860 J/(kg °C)

ΔT = Q/mc = 30 × 10⁷ J/0.017 kg × 860 J/(kg °C)

     = 30 × 10⁷/14.62

     = 2.05 × 10⁷ °C

5 0
2 years ago
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If u walk to school at a speed of 1.2 m/s and it takes you 18 min to reach the school, what is the distance from your home to th
Reptile [31]

Answer:

21.6m

Explanation:

Distance=speed×time

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