All categories

3 years ago

Help me asap please i beg lol

Mathematics

2 answers:

Furkat [3]3 years ago

6 0

Answer:

-3, 3

Step-by-step explanation:

drek231 [11]3 years ago

4 0

Answer:

There are 2 ways to find slope:

You can either take any 2 points on the graph and plug in the values for this equation: y2-y1 / x2-x1 where y2 is the value of y for the second point, x1 is the x value of the first point and so on. Or you can find the distance from any 2 points on the line by putting the amount gone up over the amount horizontally. For example from (0, -3) to (3, 0) we go up 3 units and to the right 3 units. Remember to put the amount gone up/down over the amount gone left/right. 3/3 is the slope and 3/3 is equal to 1.

the slop is 1

Step-by-step explanation:

You might be interested in

-5 = w-3 what is w<br> please help

Ann [662]

Answer

w=-2

Step-by-step explanation:

-5=w-3

-5+3=w-3+3

-2=w

plezz give me brainiest

7 0

3 years ago

It has been found that 85.6% of all enrolled college

NNADVOKAT [17]

Answer:

it has been found that 85.6% of all enrolled college and university students in the U.S. are undergraduates. A random sample of 500 enrolled college students in a particular state revealed that 420 of them were undergraduates. Is there sufficient evidence to conclude that the population differs from the national percentages? Use a = 0.05

6 0

3 years ago

A presidential candidate's aide estimates that, among all college students, the proportion who intend to vote in the upcoming el

inessss [21]

Answer:

$z=\frac{0.529 -0.6}{\sqrt{\frac{0.6(1-0.6)}{240}}}=-2.24$

$p_v =P(z$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion college students expressed an intent to vote is not higher than 0.6

Step-by-step explanation:

Assuming the following question: A presidential candidate's aide estimates that, among all college students, the proportion p who intend to vote in the upcoming election is at least 60% . If 127 out of a random sample of 240 college students expressed an intent to vote, can we reject the aide's estimate at the 0.1 level of significance?

Data given and notation

n=240 represent the random sample taken

X=127 represent the college students expressed an intent to vote

$\hat p=\frac{127}{240}=0.529$ estimated proportion of college students expressed an intent to vote

$p_o=0.6$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that at least 60% of students are intented to vote .:

Null hypothesis: $p \geq 0.6$

Alternative hypothesis: $p < 0.6$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.529 -0.6}{\sqrt{\frac{0.6(1-0.6)}{240}}}=-2.24$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

7 0

3 years ago

Given the following rst-order IVP: (e x + y) dx + (2 + x + yey ) dy = 0 y (0) = 1 (a) Show that this equation is exact. (b) Solv

ankoles [38]

Answer:

let M=ex +y and N=2 +x +yey

(a) σM/σy =1 and σN/σx = 1

since σM/σy = σN/σx , it is an exact equation

(b) ∫M dx + ∫terms of N not containing x

∫(ex + y) dx +∫yey + 2 dy

xy + ex +yey -ey +2y=C

C=3

(d) from the differential equation given

by dividing through by dx

dy/dx = (-y-ex) /(2+x+yey)

from the solution

$\frac{d}{dx}$ (xy + ex +yey -ey =2y)= $\frac{d}{dx}$ (3)

x $\frac{dx}{dy}$ + y + ex + yey $\frac{dy}{dx}$ + ey $\frac{dx}{dy}$ - ey $\frac{dy}{dx}$ + 2 $\frac{dy}{dx}$ = 0

$\frac{dy}{dx}$ = (-y-ex) /(2+x+yey)

Step-by-step explanation:

1. integrate with respect to x keeping y constant

2. integrate terms without x in N

3. Result of 1 + result 2= C

4. insert the condition given into 3

5. compare the solution of 4 to the differential equation

7 0

3 years ago

1.Show that the statement p: “If x is a real number such that x3 + 4x = 0, then x is 0” is true by

Genrish500 [490]

If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.

8 0

3 years ago