16x^2=9
x^2=9/18
x=sqrt(9/16)
x=3/4,-3/4
so the root of the quadratic equation are 3/4 and -3/4
Answer:
Step-by-step explanation:
ABC have sides: 5, 7 and 10
5^2 + 7^2 = 25+47 = 72 < 10^2
so triangle ABC is obtuse
JKL has sides: 12, 35 and 37
12^2 + 35^2 = 144 + 1225 = 1369 = 37^2
so triangle JKL is right-angled
PQR has sides 12, 10 and 16
12^2 + 10^2 = 144 + 100 = 244 > 16^2
so triangle PQR is acute
Answer:
oh thats cool
Step-by-step explanation:
Answer:
48
Step-by-step explanation:
x = -2 y =3
3x² - 2xy²
3(-2)² -2(-2)(3)²
square first
3*4 -2(-2)*9
multiplty from left to right
12-2(-2)*9
multiply from left to right again
12 -(-36) subtract using rule for integers that double minus is plus
12 + 36
48
