Question

Which of the following points would be on the graph of the equation y=−4x+6?(−4, −10)(−4, 22)(1, −10)(1, −2)

Answer 1

Answer:

Only the point (-4, 22)  is ON THE GRAPH of the equation. Please also check the attached graph.

Step-by-step explanation:

Given the equation

$y=-4x+6$

Let us substitute all the given points to check which points satisfy the equation.

Substitute (-4, -10) in the equation

$y=-4x+6$

$-10=-4(-4)+6$

$-10=16+6$

$-10=22$

As the R.H.S ≠ L.H.S, hence (-4, -10) does not satisfy the equation.

Hence, (-4, -10) is NOT ON THE GRAPH of the equation

Substitute (-4, 22) in the equation

$y=-4x+6$

$22 = -4(-4)+6$

$22 = 16+6$

$22 = 22$

As the R.H.S = L.H.S, hence (-4, 22) satisfies the equation.

Hence, (-4, 22)  is ON THE GRAPH of the equation. Please also check the attached graph.

Substitute (1, -10) in the equation

$y=-4x+6$

$-10=-4(1)+6$

$-10=-4+6$

$-10=2$

As the R.H.S ≠ L.H.S, hence (1, -10) does not satisfy the equation.

Hence, (1, -10) is NOT ON THE GRAPH of the equation

Substitute (1, -2) in the equation

$y=-4x+6$

-2 = -4(1)+6

-2 = -4 + 6

-2 = 2

As the R.H.S ≠ L.H.S, hence (1, -2) does not satisfy the equation.

Hence, (1, -2) is NOT ON THE GRAPH of the equation

Therefore, from the above analysis, we conclude that only the point (-4, 22)  is ON THE GRAPH of the equation. Please also check the attached graph.