<span>
You can write the equation in point-slope form, which has the format <em>y-y</em>subscript1=<em>m</em>(<em>x-x</em>subscript1), with <em>y</em>subscript1 and <em>x</em>subscript1 being the y and x coordinates for a point on the line, and <em>m</em> being the slope. </span>
<span /><span>Substitute a y and x coordinate into the equation so you have <em>y</em>-6=<em>m</em>(<em>x</em>-2)</span>
<span /><span><span>Then find the slope so you can replace <em>m</em>. The slope formula is <em />(<em>y</em>subscript2-<em>y</em>subscript1)/(<em>x</em>subscript2-<em>x</em>subscript1). </span><span>Substitute the coordinates in so you have <em>m</em>=(16-6)/(4-2), which simplifies to 10/2 and then 5.</span></span>
<span><span /></span><span>Now the equation is <em>y</em>-6=5(<em>x</em>-2)</span>
<span />If you want a different form, for example slope-intercept form, you can change it to that:
<span><em>y</em>-6=5(<em>x</em>-2)</span>
<span><em>y</em>=5x-4</span>
Answer:
area of rhombus =1/2 d1×d2
20=1/2 ×10×d2
d2=4
intersection of diagonal make right angle and cut in equal parts
d1/2=10/2=5
d2/2=4/2=2
use Pythagoras in right angle to bide side
side^2= 5^2 +2^2
side = √29
Answer:
answer a
Step-by-step explanation:
< 
- Let's isolate
on one side of the equation. Ignore the inequality for now. We'll deal with that later.

- Now, I'm going to bring back the inequality or < symbol. I only removed it when simplifying and isolating
, but if this confuses you, just do your math and keep the inequality there.
< 
- On a number line, this would include every number <em>less than </em>
, due to the < (less than) symbol. This disqualifies answers b and d because they are showing every number <em>greater than </em>
. But, how do we decide between answers a and c? - If a line has point at its beginning,
, then that means that every number <em>less than or equal to</em> [ ≤ ] 6 is being shown, but our equation just says <em>less than </em>[ < ] 6, so answer a is our correct answer.
Answer equals 1
Step-by-step explanation:
It's not a hard question
Answer:
Alternative C is the correct answer
Step-by-step explanation:
The first step is to determine the composite function;
![f[g(x)]](https://tex.z-dn.net/?f=f%5Bg%28x%29%5D)
![f[g(x)]=cos[cot(x)]](https://tex.z-dn.net/?f=f%5Bg%28x%29%5D%3Dcos%5Bcot%28x%29%5D)
We then employ a graphing utility to determine the range and the domain of the new function.
The range is the set of y-values for which the function is defined. In this case it is;
![[-1,1]](https://tex.z-dn.net/?f=%5B-1%2C1%5D)
On the other hand, the domain refers to the set of the x-values for which the function is real and defined. In this case; it is the set of real numbers x except x does not equal npi for all integers n.