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spin [16.1K]
2 years ago
7

The point, (-4, 1) is located in which quadrant?

Mathematics
1 answer:
gogolik [260]2 years ago
4 0
It is located at quadrant 2. Quadrant one is the top right side. Quadrant three is the bottom left side. Quadrant four is the bottom right side.
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Write an expression so that when u divided 1/4 by a number the answer will be larger
Viktor [21]
20x1/4=5
Think thats what you mean
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In 1997 the interest category for 12% of all new magazines was sports. This describes a parameter. True or false
algol13
False ....a parameter is something YOU can change, like asking magazines if they are interested in sports, or interested in photography, or something else. So the 12% is a statistic.
6 0
3 years ago
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Find x on this special right triangle, 45 is not an option!!!!
zloy xaker [14]

let the line between 2 tria be y

sin 60/8√2 = sin 90/y

y=13.06

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7 0
2 years ago
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Which equation has the solutions x = -3 ± √3i/2 ?
Maurinko [17]

Answer:Answer is option C : [x^{2} + 3x + 3 ] =0

Note:  None of options matches with given question.

instead of "-3" , there should be "-\frac{3}{2}".

Step-by-step explanation:

Note:  None of options matches with given question.

instead of "-3" , there should be "\frac{3}{2}".  

Here, First thing you have to observe the nature of roots.

∴ x = -\frac{3}{2}+\frac{\sqrt{3}}{2}i and x = -\frac{3}{2}-\frac{\sqrt{3}}{2}

∴ [ x+(\frac{3}{2}-\frac{\sqrt{3}}{2}i) ][ x+(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [ x^{2} + x(\frac{3}{2}+\frac{\sqrt{3}}{2}i)+ x(\frac{3}{2}-\frac{\sqrt{3}}{2}i) + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [x^{2} + \frac{3}{2}x + \frac{\sqrt{3}}{2}ix + \frac{3}{2}x - \frac{\sqrt{3}}{2}ix + (3-\frac{\sqrt{3}}{2}i)(3+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{\sqrt{3}}{2}i)(\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{3}{4}) i^{2} ] =0

∴ [x^{2} + 3x + \frac{9}{4} + (\frac{3}{4}) ] =0

∴ [x^{2} + 3x + \frac{12}{4} ] =0  

∴ [x^{2} + 3x + 3 ] =0  

Thus, Answer is option C : <em>[x^{2} + 3x + 3 ] =0  </em>

6 0
3 years ago
Standard form Q)9, Q)10
jeka94
9) 0.31
10) (7x10^6)-(3x10^3)
7000000-3000=6997000
6.997x10^6

Hope this helps :)
7 0
3 years ago
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