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Mademuasel [1]
3 years ago
8

HELP FAST PLZ

Mathematics
2 answers:
Stells [14]3 years ago
8 0

Answer:

$236 in 3 years

Step-by-step explanation:

Liula [17]3 years ago
3 0
He would be paid $236 for the 3years
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A composition of reflections across two intersecting lines is a _____
kogti [31]

A composition of reflections across two intersecting lines is a rotation.


I hope helped ^^

4 0
3 years ago
Hannah,her dad,and her grandmother each ate 2/8. How much pizza did they eat altogether?
Vinil7 [7]

Answer:

6/8

Step-by-step explanation:

2/8 + 2/8 + 2/8 = 6/8.

Add the tops. Hope this helps :)

7 0
3 years ago
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What is 3/4 of 240 4/5?
OLEGan [10]
180.6 is the answer 240 4/5 is 240.8
240.8/4 is 60.2
60.2 x 3 is your answer
6 0
3 years ago
Suppose that a local TV station conducts a survey of a random sample of 120 registered voters in order to predict the winner of
forsale [732]

Answer:

a) The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b) The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

Sample of 120 registered voters in order to predict the winner of a local election. The Democrat candidate was favored by 62 of the respondents.

So 120 - 62 = 58 favored the Republican candidate, so:

n = 120, \pi = \frac{58}{120} = 0.4833

99% confidence level

So \alpha = 0.01, z is the value of Z that has a p-value of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 - 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.3658

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 + 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.6001

The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b. If a candidate needs a simple majority of the votes to win the election, can the Republican candidate be confident of victory? Justify your response with an appropriate statistical argument.

The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

8 0
3 years ago
A researcher is interested in knowing the average height of the men in a village. To the researcher, the population of interest
Anna11 [10]

Answer:

The population mean height of men in the village is 5.78 feet.

The sample mean height of men in the village is 7.8 feet.

Step-by-step explanation:

It is provided that the researcher's interest is in knowing the average height of the men in a village.

To the researcher, the population of interest is the <em><u>men</u></em><em> </em>in the village, the relevant population data are the <em><u>height of men</u></em> in the village, and the population parameter of interest is the <em><u>mean height of men</u></em>.

It is also provided that there are 590 men in the village, and the sum of their heights is 3,410.2 feet.

Compute the average height as follows:

\bar X_{H}=\frac{3410.2}{590}=5.78\ \text{feet}

Thus, the population mean height of men in the village is 5.78 feet.

It is given that the researcher measured the heights of 18 village men and calculated the average to estimate the average height of all the village men.

The sample for his estimation is <em><u>18 men</u></em>, the relevant sample data are the <em><u>heights of the 18 men</u></em>, and the sample statistic is the <em><u>sample mean height</u></em>.

It is also given that the  sum of the heights of the 18 village men is 104.4 feet.

Compute the average height of the 18 men as follows:

\bar x_{H}=\frac{104.4}{18}=7.8\ \text{feet}

Thus, the sample mean height of men in the village is 7.8 feet.

8 0
3 years ago
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