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3 years ago

15

Vcvvvv

1 answer:

VARVARA [1.3K]3 years ago

5 0

I'm not sure Google it tho might help

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Wewaii [24]

13 hours
200 divided by 15 = 13.33333333333333
So since this a long number I have to round.
Answer: 13 hours

5 0

4 years ago

Read 2 more answers

Will mark brainless for first response!!!

ivann1987 [24]

1. (2x + 1)(x - 7)
2. -x - 4
3. -31x -35
4. 57x + 112
5. (-x) (-x)

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3 years ago

What is the simplified form of 3/4x+3+21/8x^2-14x-15

creativ13 [48]

Solution:

We have been asked to find the simplified expression of

$3/4x+3+21/8x^2-14x-15=\frac{3}{4x+3} +\frac{21}{8x^2-14x-15}\\ \\ \text{We will have to make the denominator equal to add}\\ \\ \ 8x^2-14x-15=8x^2+6x-20x-15\\ \\ \ =2x(4x+3)-5(4x+3)=(4x+3)(2x-5)\\ \\ \frac{3}{4x+3} +\frac{21}{8x^2-14x-15}=\frac{3}{4x+3} +\frac{21}{(4x+3)(2x-5)}\\ \\ =\frac{3(2x-5)+21}{(4x+3)(2x-5)}\\ \\ =\frac{6x-15+21}{(4x+3)(2x-5)} \\ \\ =\frac{6x+6}{(4x+3)(2x-5)} \\$

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2

Nimfa-mama [501]

First of all, we can observe that

$x^2-6x+9 = (x-3)^2$

So the expression becomes

$\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}$

This means that the expression is defined for every $x\neq 3$

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

$x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2$

Since we can't accept 3 as an answer, the actual solution set is

$(-\infty,-2] \cup [2,3) \cup (3,\infty)$

7 0

3 years ago

Need help please :) thanks

Trava [24]

K’ (-3,-3)
L’(1,-1)
M’(-1,-5)
N’(-5,-7)

D’(0,4)
E’(4,3)
F’(2,-5)
G’(-2,-4)

5 0

3 years ago