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grandymaker [24]
3 years ago
10

How many grams is cacl2are there in 2.5moles?

Chemistry
2 answers:
geniusboy [140]3 years ago
8 0

Answer:

277,46Explanation:

White raven [17]3 years ago
5 0

Answer:

There are 277.5 grams of CaCl₂ in 2.5 moles

Explanation:

The mass of a mole of a substance is known as its molar mass. It is defined as the mass of the amount of a substance which contains the elementary number of particles, 6.0 * 10²³.

The molar mass of calcium chloride, CaCl₂ is obtained by adding the sum of the atomic masses of the elements present in the compound.

Atomic mass of calcium, Ca, is 40 g/mol; atomic mass of chlorine, Cl, is 35.5 g/mol. Therefore, the molar mass of CaCl₂ = (40 + 2 * 35.5) g = (40 + 71) g = 111.0 g. Therefore, molar mass of CaCl₂ is 111.0 g/mol

Since there are 2.5 moles of CaCl₂ in the sample, its mass in grams = number of moles * molar mass of CaCl₂

mass in grams = 2.5 * 111.0 g = 277.5 g

Therefore, there are 277.5 grams of CaCl₂ in 2.5 moles

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An iron ore sample weighing 0.5562 g is dissolved HCl (aq), and the iron is obtained as Fe2 in solution. This solution is then t
erik [133]

Answer:

\% Fe^{+2}=70%

Explanation:

Hello,

In this case, we could considering this as a redox titration:

Fe^{+2}+(Cr_2O_7)^{-2}\rightarrow Fe^{+3}+Cr^{+3}

Thus, the balance turns out (by adding both hydrogen ions and water):

Fe^{+2}\rightarrow Fe^{+3}+1e^-\\(Cr_2^{+6}O_7)^{-2}+14H^++6e^-\rightarrow 2Cr^{+3}+7H_2O\\\\6Fe^{+2}+(Cr_2^{+6}O_7)^{-2}+14H^++6e^-\rightarrow Cr^{+3}+7H_2O+6Fe^{+3}+6e^-

Thus, by stoichiometry, the grams of Fe+2 ions result:

m_{Fe^{+2}}=0.04021\frac{molK_2Cr_2O_7}{L}*0.02872L*\frac{6molFe^{+2}}{1molK_2Cr_2O_7}*\frac{56gFe^{+2}}{1molFe^{+2}}=0.388gFe^{+2}

Finally, the mass percent is:

\% Fe^{+2}=\frac{0.388g}{0.5562g}*100\%\\  \% Fe^{+2}=70%

Best regards.

8 0
3 years ago
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