1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vekshin1
3 years ago
11

A horizontal row of the periodic table is usually referred to as a ____________

Chemistry
2 answers:
zaharov [31]3 years ago
8 0

the answer is period

Fofino [41]3 years ago
3 0
Referred to as a “period”
You might be interested in
Gaseous methane (CH4) reacts with gaseous oxygen gas (02) to produce gaseous carbon dioxide (CO2) and gaseous water (H20). What
Mariana [72]

Answer:

Theoretical yield = 3.51 g

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

For CH_4  :-

Mass of CH_4  = 1.28 g

Molar mass of CH_4  = 16.04 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{1.28\ g}{16.04\ g/mol}

Moles_{CH_4}= 0.0798\ mol

For O_2  :-

Mass of O_2  = 10.1 g

Molar mass of O_2  = 31.998 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{10.1\ g}{31.998\ g/mol}

Moles_{O_2}= 0.3156\ mol

According to the given reaction:

CH_4+2O_2\rightarrow CO_2+2H_2O

1 mole of methane gas reacts with 2 moles of oxygen gas

0.0798 mole of methane gas reacts with 2*0.0798 moles of oxygen gas

Moles of oxygen gas = 0.1596 moles

Available moles of oxygen gas = 0.3156 moles

<u>Limiting reagent is the one which is present in small amount. Thus, CH_4 is limiting reagent. </u>

The formation of the product is governed by the limiting reagent. So,

1 mole of methane gas on reaction produces 1 mole of carbon dioxide.

0.0798 mole of methane gas on reaction produces 0.0798 mole of carbon dioxide.

Mole of carbon dioxide = 0.0798 mole

Molar mass of carbon dioxide = 44.01 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0798\ moles= \frac{Mass}{44.01\ g/mol}

Mass of CO_2 = 3.51 g

<u> Theoretical yield = 3.51 g</u>

3 0
3 years ago
What volume does .0685 mol of gas occupy at STP? 1mole =22.4
GuDViN [60]
V = nRT/P
V = 0.685 mol*(.0821 L*atm/K*mol)*273 K/1 atm
4 0
3 years ago
Read 2 more answers
Famous New Zealand scientist Ernest Rutherford was awarded a Nobel Prize in which field?
Gnom [1K]
The  field of Chemistry. 
4 0
3 years ago
Please help like please
klemol [59]

Answer:

It is the third one

Explanation:

"Both atoms achieve a more stable configuration."

4 0
2 years ago
Read 2 more answers
What is difference between layer A and layer b? ​
lakkis [162]

Answer:

can you send me a picture of what layer a and look b look like and then I will be able to evaluate

7 0
3 years ago
Other questions:
  • Dichloromethane contains strong carbon - hydrogen and carbon- chlorine bonds. Despite the presence of these strong bonds. dichlo
    11·1 answer
  • How many protons electrons and neutrons respectively does 29 CS have
    12·1 answer
  • Does a dry cell have local action?​
    7·1 answer
  • Jwjajajahwhab a a skwiwiwiahah​
    7·2 answers
  • Carbon NMR spectroscopy produces a spectrum of only carbon-13 nuclei in a sample. The number of carbon signals in the spectrum c
    7·1 answer
  • Why doesn't the steepness of a frictionless ramp affect the velocity of the block at the bottom of the ramp? (Hint: Discuss cons
    10·1 answer
  • URGENT PLS HELP What are derived units?
    5·1 answer
  • Which statement describes ONLY the Quantum Mechanical model of the atom? A) Energy Is quantized B) Has discrete energy levels. H
    5·1 answer
  • Which of the following compounds has the general formula X3Y2?Which of the following compounds has the general formula X3Y2?
    11·1 answer
  • Hey hey hey hey hey hey hey bye
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!