Answer:
V = 19m/s
Explanation:
Given the following data;
Initial velocity, U = 4m/s
Acceleration, a = 0.5m/s²
Time, t = 30 seconds
To find the final velocity, we would use the first equation of motion;
V = U + at
Where;
V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.
V = 4 + 0.5*30
V = 4 + 15
V = 19m/s
Therefore, his final velocity is 19 meters per seconds.
Answer:
ig d. transmits only green light.....
Answer:
A.
Explanation: both triple by 3
Responder:
Explicación:
Para que podamos calcular el tiempo que le tomará al esquiador permanecer en el aire, encontraremos el tiempo de vuelo como se muestra;
T = 2Usin theta / 2
theta = 90 grados
U = 25 m / s
T = 25sin90 / 2 (9,8)
T = 25 / 19,62
T = 1,27 segundos
Por lo tanto, los cielos usarán 1.27 segundos en el aire.
La distancia horizontal es el rango;
Rango R = U√2H / g
R = 25√2 (80) /9,8
R = 25√160 / 9,8
R = 25 * √16,326
R = 25 * 4.04
R = 101,02 m
Por tanto, la distancia horizontal recorrida por el esquiador es 101,02 m
