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Musya8 [376]
3 years ago
12

Paco was driving his scooter west with an initial velocity of 4 m/s. He accelerates at 0.5 m/s2 for 30 seconds.

Physics
2 answers:
KonstantinChe [14]3 years ago
6 0

Answer:

V = 19m/s

Explanation:

Given the following data;

Initial velocity, U = 4m/s

Acceleration, a = 0.5m/s²

Time, t = 30 seconds

To find the final velocity, we would use the first equation of motion;

V = U + at

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

V = 4 + 0.5*30

V = 4 + 15

V = 19m/s

Therefore, his final velocity is 19 meters per seconds.

Norma-Jean [14]3 years ago
4 0

Answer:

its C)19

Explanation:

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Answer:

Explanation:

Given

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Particle will be at equilibrium when Potential Energy is either minimum or maximum

F=-\left ( 2ax-\frac{2b}{x^3}\right )

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x_0=(\frac{b}{a})^{0.25}

So angular Frequency of small oscillation is given by

\omega =\sqrt{\frac{U''(x)}{m}}

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3 years ago
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xxTIMURxx [149]

Answer:

12.7m/s

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Mass of the diver = 77kg

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            v²  = u² + 2gh

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That's "<em>DC</em>" . . . Direct Current .

8 0
3 years ago
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A block has a volume of 0.09 m3 and a density of 4,000 kg/m3. What's the force of gravity acting on the block in water?
12345 [234]

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                                4,000 kg/m³ = (mass) / (0.09 m³)

Multiply each side
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Force of gravity = (mass) x (acceleration of gravity)

                           = (360 kg) x (9.8 m/s²)

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That's the force of gravity on this block, and it doesn't matter
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The block is displacing 0.09 m³ of water.  Water has 1,000 kg of
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So while it's in the water, the block seems to weigh

       (3,528  -  882) = 2,646 newtons  (about 595.2 pounds) .

But again ... it's not correct to call that the "force of gravity acting
on the block in water".  The force of gravity doesn't change, but
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