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maxonik [38]
3 years ago
9

Pick a one world factor to describe the benefits and limitations of Bromine

Chemistry
1 answer:
motikmotik3 years ago
7 0

A one world factor to describe the benefits and limitations of Bromine are water purification compound.

Explanation:

Benefits of bromine

  • Bromine is used to make organobromo compounds.
  • Dibromoethane is an agent for leaded gasoline, largely stepped out due to environmental considerations.  
  • In fire extinguishers, pharmaceutical products and insecticides, organobromines are used.  
  • Bromine applied in dyes production, water purification compounds, fumigants, sanitizes, medicinal,  photography, flame proofing agents.
  • In citrus beverages, bromine used as emulsifier.

Limitations of bromine

  • Organic bromines are used as protecting and disinfecting agents, because microorganisms has its damaging effect. Once it is used in greenhouses and on farmland they can easily wash off to surface water, which has negative health effects on algae, daphnia, lobsters and fishes.
  • The animals effected on DNA damage and nerve damage which can leads to development of cancer.
  • Organic bromines can damage organs such as kidneys, liver, lungs.
  • Ethylene bromine can cause cancer.

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If I initially have a gas at a pressure of 12 atm, volume of 23 liters, and temperature of 200 K, and then I raise the pressure
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Answer : The volume of gas will be 29.6 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 12 atm

P_2 = final pressure of gas = 14 atm

V_1 = initial volume of gas = 23 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 200K

T_2 = final temperature of gas = 300K

Now put all the given values in the above equation, we get the final pressure of gas.

\frac{12atm\times 23L}{200K}=\frac{14\times V_2}{300K}

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Calculate the vapor pressure of a solution of 32.5 g of glycerol (C3H8O3) in 500.0 g of water at 25°C. The vapor pressure of wat
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The vapor pressure is obtained as 23.47 torr.

<h3>What is the vapor pressure?</h3>

Given that; p = x1p°

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x1 = mole fraction of the solvent

p° = vapor pressure of the pure solvent

Δp = p°(1 - x1)

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Number of moles of  glycerol =  32.5 g/92 g/mol = 0.35 moles

Number of moles  of water = 500.0 g/18 g/mol = 27.8 moles

Total number of moles = 0.35 moles + 27.8 moles = 28.15 moles

Mole fraction of glycerol = 0.35 moles/28.15 moles = 0.012

Mole fraction of water = 27.8 moles/28.15 moles =0.99

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Δp =  0.285 torr

p1 = p° - Δp

p1 = 23.76 torr -  0.285 torr

p1 = 23.47 torr

Learn more about vapor pressure:brainly.com/question/14718830

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