Answer:
h(-6) = -22
Step-by-step explanation:
h(n) = 3n - 4
h(-6)= 3(-6) - 4
= -18 - 4
= -22
Answer:
H(s)=(∫_(t=o)^∞▒〖x(t)e^(-st) dt〗)/(∫_(t=o)^∞▒〖y(t) e^(-st) dt〗)
Step-by-step explanation:
L{f(t)}=F(s)=∫_(t=0)^∞▒〖f(t)e^(-st) dt〗
27y^3 -343 starts out with 27y^3, and 343 is the cube of 7. Thus, we know immediately that 27y3 -343 is the diffeence of two squares.
The appropriate rule is a^3 - b^3 = (a - b)(a^2 + ab + b^2).
Here, we have 27y3 -343 = (3y - 7)(9y^2 + 12y + 49)
Answer:
1 and 2/3
Step-by-step explanation:
5/3 = 1 and 2/3 * 1 = 1 and 2/3
Answer:
r = -40
Step-by-step explanation:
1. Move constants to the other side of the equation
r = 16/-.04
2. Simplify (by calculator)
You can use a calculator and plug in 16/-.04
r = -40
2. Simplify (by fraction)
You can turn -.4 into a fraction.
-.04 = - 4/10
r = 16/-(4/10)
r = 16*10/-4
r = -40
