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3 years ago

15

I need someone who is great with trig to help me with some Qs on my profile

1 answer:

Svetradugi [14.3K]3 years ago

8 0

Answer:

Ok.

Step-by-step explanation:

Since I will help you, can I get brainliest?

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Find the least number which when divisible by 20, 24, 32 and 38 leaves a remainder 5 in cach case

Olegator [25]

Answer:

18245

Step-by-step explanation:

We have to use L.C.M,

L.C.M(20,24,32,38)

2|20,24,32,38

2| 10 ,12 ,16 ,19

2| 5 , 6 , 8 , 19

2| 5 , 3 , 4 , 19

2| 5 , 3 , 2 , 19

L.C.M = 2 x 2 x 2 x 2 x 2 x 2 x 5 x 3 x 19

= 18240

Now for each case remainder is 5,

So the number is 18240+5

=> 18245

7 0

3 years ago

A parabola can be represented by the equation y2 = –x. What are the coordinates of the focus and the equation of the directrix?

Vilka [71]

(y-k)²=4p(x-h)
(h,k) is vertex
and since we got the y term squred, it is facing left or right
when p is positive, then focus is to right of veretx
p is distance from focus to vertex and from vertex to dirextix

y²=-x
(y-0)²=4(-1/4)(x-0)
vertex is (0,0)
p is negative so then focus to left of vertex
so the focus is (-1/4,0)
dirextix is x=1/4

8 0

2 years ago

Read 2 more answers

Of 136 randomly selected adults, 33 were found to have high blood pressure. Construct a 95% confidence interval for the true of

navik [9.2K]

Answer:

The 95% confidence interval of the proportion of all adults that have high blood pressure is 0.17059 < $\hat{p}$ < 0.314695

Step-by-step explanation:

The confidence interval for a proportion is given by the following formula;

$CI=\hat{p}\pm z\times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$

Where:

x = 33

n = 136

$\hat{p}$ = x/n = 33/136 = 0.243

z value for 95% confidence is 1.96

Plugging in the values, we have;

$CI=0.243\pm 1.96\times \sqrt{\frac{0.243(1-0.243)}{136}}$

Which gives;

0.17059 < $\hat{p}$ < 0.314695

Hence the 95% confidence interval of the proportion of all adults that have high blood pressure = 0.17059 < $\hat{p}$ < 0.314695

From the above we have;

23.2 < x < 42.798

Since we are dealing with people, we round down as follows;

23 < x < 42.

4 0

2 years ago

What is 7 3/10 as a percent

spin [16.1K]

730% is the answer!!

5 0

3 years ago

Read 2 more answers

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0

3 years ago