For a you will see a bar graph and the dependent o think would be bird species
The answer can be readily calculated using a single variable, x:
Let x = the amount being invested at an annual rate of 10%
Let (8000 - x) = the amount being invested at an annual rate of 12%
The problem is then stated as:
(x * 0.10) + ((8000 - x) * 0.12) = 900
0.10(x) + ((8000 * 0.12) - 0.12(x)) = 900
0.10(x) + 960 - 0.12(x) = 900
0.10(x) - 0.12(x) = 900 - 960
-0.02(x) = -60
-0.02(x) * -100/2 = -60 * -100/2
x = 6000 / 2
x = 3000
Thus, $3,000 is invested at 10% = $300 annually; and $8,000 - $3,000 = $5,000 invested at 12% = $600 annually, which sum to $900 annual investment.
Answer:
£15
Step-by-step explanation:
Angad : Nick = 5 : 1
Let
Nick share = x
Angad share = x + £60
Angad : Nick
5 : 1 = x + £60 : x
5/1 = x + 60 / x
Cross product
5 * x = 1 * x + 60
5x = x + 60
5x - x = 60
4x = 60
x = 60/4
x = 15
Nick get £15
Answer:
152
Step-by-step explanation:
The amount of fish caught is at a constant decreasing rate of 17. 203-186=17, 186-169=17, 169-17=152. So all you have to do is subtract the constant rate from the last known number.
Answer:
nicce
Step-by-step explanation: