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Ahat [919]
2 years ago
5

An express bus and local bus start out at 1rst street together. The express bus stops every 15 blocks. The local bus stops every

4 blocks. How many blocks will it be before there is a bus stop where both buses stop?
HELPPP
Mathematics
1 answer:
n200080 [17]2 years ago
3 0

Answer:

60

Step-by-step explanation:

15,30,45,60

4,8,12,16,20,24,28,32,36,40,44,48,52,56,60

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5. What is the value of x?<br> A)15 Square root 3 B)15/2 C)5 Square root 3 D)15 Square root 2/2
zhannawk [14.2K]

Answer:

5√3

Step-by-step explanation:

7 0
3 years ago
Please help me with the answer!! There is the picture of the problem^
Gnoma [55]

Answer:

6

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
PLEASE HELP!!
PSYCHO15rus [73]

<u><em>Answer:</em></u>

The bird is approximately 9 ft high up in the tree

<u><em>Explanation:</em></u>

The required diagram is shown in the attached image

Note that the tree, the cat and the ground form a right-angled triangle

<u>Therefore, we can apply special trigonometric functions</u>

<u>These functions are as follows:</u>

sin(\alpha)=\frac{opposite}{hypotenuse} \\ \\ cos(\alpha)=\frac{adjacent}{hypotenuse} \\ \\tan(\alpha)=\frac{opposite}{adjacent}

<u>Now, taking a look at our diagram, we can note the following:</u>

α = 25°

The opposite side is the required height (x)

The adjacent side is the distance between the cat and the tree = 20 ft

Therefore, we can use the <u>tan function</u>

<u>This is done as follows:</u>

tan(\alpha)=\frac{opposite}{adjacent}\\ \\ tan(25)=\frac{x}{20}\\ \\x=20tan(25) = 9. 32 ft which is 9 ft approximated to the nearest ft

Hope this helps :)

5 0
3 years ago
SOMEONS PLEASE HELP ME I will mark brainliest!!!
tresset_1 [31]

Answer:

x=9

Step-by-step explanation:

because I asked my in-collage brother who told me

<h2>*<u><em>THIS USER HAS BEEN VERIFIED AND ACCEPTED AS AN OFFICIAL BRAINLY© USER, ALLOWING THAT YOU GOT LUCKY FOR HAVING A PRO ANSWER THIS QUESTION*</em></u></h2>
8 0
3 years ago
Use Gauss-Jordan elimination to solve the following linear system.
marysya [2.9K]
Just put the coefients in to a matrix

1x-6y-3z=4
-2x+0y-3z=-8
-2x+2y-3z=-14

\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\-2&2&-3|-14\end{array}\right]
mulstiply 2nd row by -1 and add to 3rd
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&2&0|-6\end{array}\right]
divde last row by 2
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 2rd row by 6 and add to top one
\left[\begin{array}{ccc}1&0&-3|-14\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 1st row by -1 and add to 2nd
\left[\begin{array}{ccc}1&0&-3|-14\\-3&0&0|6\\0&1&0|-3\end{array}\right]
divide 2nd row by -3
\left[\begin{array}{ccc}1&0&-3|-14\\1&0&0|-2\\0&1&0|-3\end{array}\right]
mulstiply 2nd row by -1 and add to 1st row
\left[\begin{array}{ccc}0&0&-3|-12\\1&0&0|-2\\0&1&0|-3\end{array}\right]
divide 1st row by -3
\left[\begin{array}{ccc}0&0&1|4\\1&0&0|-2\\0&1&0|-3\end{array}\right]

rerange
\left[\begin{array}{ccc}1&0&0|-2\\0&1&0|-3\\0&0&1| 4\end{array}\right]

x=-2
y=-3
z=4
(x,y,z)
(-2,-3,4)

B is answer
7 0
3 years ago
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