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bonufazy [111]
3 years ago
6

Ribosomes provide the scaffolding on which trnas interact with mrna during translation of an mrna sequence to a chain of amino a

cids. A ribosome has three binding sites. What are these three binding sites?
Biology
1 answer:
BlackZzzverrR [31]3 years ago
5 0

Answer:

<h2>Rbosomes contain three binding sites: the A site, the P site, and the E site </h2>

Explanation:

1. Protein synthesis occurs with the combination of ribosomes (large subunit and small subunit) mRNA and tRNA.  

2. mRNA contains nucleotide sequences in the form off codons, which codes specific amino acids according to their bases.

3. tRNA contains anti-codons, and according to the codons in mRNA, tRNA brings amino acids to the ribosomes and the synthesis of protein occurs.

4. Ribosome has three binding sites: The A site, the P site, and the E site. First of all, an aminoacy-tRNAs (a tRNA containing amino acid covalently attached) first enter the ribosome at the A site, and then to P site and finally exits via E site.

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The number of cells in an average-sized adult human is on the order of 10^14 cells. Use this information, and the estimate that
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IF:
Number of cells: C = 10^{14}
DNA lenght: D = 2m = 12.42 * 10^{-4} mi
Distance from Earth to Sun: ES=93000000 mi = 9.3* 10^{7}mi

Then:
a) <span>Over how many miles would the total DNA from the average human stretch?
The answer is product of multiplication of the number of cells (C) and the DNA length (D):
Total DNA: </span>T = C*D
              ⇒ T = 10^{14}*12.42* 10^{-4} mi
              ⇒ T = 12.42* 10^{14-4} mi
              ⇒ T = 12.42* 10^{10} mi
The total DNA from the average human will stretch 12.42* 10^{10} mi

b) How many times would the total DNA from the average human stretch from Earth to the Sun and back?
The answer is concluded from the ratio of the total DNA length (T) and the <em>twice </em>(because of stretch to the Sun and back, thus, <em>two directions</em>) of distance from <span>Earth to the Sun (ES) and :
Ratio: </span>R= \frac{T}{2*ES}
      ⇒ R = \frac{12.42* 10^{10}mi }{2*(9.3* 10^{7}mi)}
      ⇒ R = \frac{12.42* 10^{10}}{18.6*10^{7}}
      ⇒ R = 0.6677* 10^{10-7}
<span>      ⇒ R = 0.6677* 10^{3}
</span><span>      ⇒ [tex]R = 667.7
</span>Thus, 667,7 times will the <span>total DNA from the average human stretch from Earth to the Sun and back.</span>
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