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Bond [772]
3 years ago
7

Write a polynomial function in standard form with given zero x=1,-2,-7

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
7 0

Answer:

f(x) = x³ + 8x² + 5x - 14

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Distributive Property

<u>Algebra I</u>

  • Terms/Coefficients/Degrees
  • Expand by FOIL (First Outside Inside Last)
  • Binomial Roots

Step-by-step explanation:

<u>Step 1: Define</u>

Zeros x = 1, -2, -7

<u>Step 2: Find Polynomial</u>

  1. Rewrite zeros:                           f(x) = (x - 1)(x + 2)(x + 7)
  2. Expand [FOIL]:                           f(x) = (x² + 2x - x - 2)(x + 7)
  3. Combine like terms (x):             f(x) = (x² + x - 2)(x + 7)
  4. Expand [Distribute]:                  f(x) = x³ + x² - 2x + 7x² + 7x - 14
  5. Combine like terms (x²):           f(x) = x³ + 8x² - 2x + 7x - 14
  6. Combine like terms (x):             f(x) = x³ + 8x² + 5x - 14
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Find the general indefinite integral. (use c for the constant of integration. )
Vlada [557]

The indefinite integral will be  \int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:                                                              

\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C

Integration Property [Multiplied Constant]:                                                        

\int cf(x)dx=c\int f(x)dx

Integration Property [Addition/Subtraction]:                                                      

\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx    -\int 2dx          

[Integrals] Rewrite [Integration Property - Multiplied Constant]:  

\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx    -2\int dx            

[Integrals] Reverse Power Rule:    

\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C                                                            

Simplify:    

\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                                                                                                      

So the indefinite integral will be \int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                

To know more about indefinite integral follow

brainly.com/question/27419605

#SPJ4

7 0
2 years ago
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