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3 years ago

Find the HCF of 30 and 45.

Mathematics

2 answers:

geniusboy [140]3 years ago

8 0

Answer:

Step-by-step explanation:

Since 30 and 45 are relatively small numbers, it's not a big deal to list every single one of their common factors.

Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30

Factors of 45: 1, 3, 5, 9, 15, 45

Now that we have a list, it's easy to see which number is the highest common factor, which is, of course, 15.

dem82 [27]3 years ago

3 0

Answer:

HCF of 30 and 45 is 15.

Step-by-step explanation:

Factors of 30 : 1, 2, 3, 5, 6, 10, 15, 30.

Factors of 45 : 1, 3, 5, 9, 15, 45.

Common Factors : 1, 3, 5, 15

Highest Common Factor : 15

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Westkost [7]

Answer:

case A. $\sqrt{18}*\sqrt{6}$

case B. $\sqrt{108}$

case E. $\sqrt{3}*\sqrt{36}$

Step-by-step explanation:

we have

$6\sqrt{3}$

we know that

$6\sqrt{3}=\sqrt{36*3}=\sqrt{108}$

<u>Verify each case</u>

case A) $\sqrt{18}*\sqrt{6}$

$\sqrt{18}*\sqrt{6}=\sqrt{18*6}=\sqrt{108}$

therefore

$\sqrt{18}*\sqrt{6}$ is equivalent to $6\sqrt{3}$

case B) $\sqrt{108}$

$\sqrt{108}$ is equivalent to $6\sqrt{3}$

case C) $\sqrt{3}*\sqrt{6}$

$\sqrt{3}*\sqrt{6}=\sqrt{18}$

therefore

$\sqrt{18}$ is not equivalent to $6\sqrt{3}$

case D) $\sqrt{54}$

$\sqrt{54}$ is not equivalent to $6\sqrt{3}$

case E) $\sqrt{3}*\sqrt{36}$

$\sqrt{3}*\sqrt{36}=\sqrt{108}$

therefore

$\sqrt{3}*\sqrt{36}$ is equivalent to $6\sqrt{3}$

case F) $108$

$108$ is not equivalent to $6\sqrt{3}$

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