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Whitepunk [10]
3 years ago
10

How do I solve this? (Geometry)

Mathematics
1 answer:
Luden [163]3 years ago
8 0

Answer:

Step-by-step explanation:

(3×10×8)÷26400= 0.00909090909

hope it helps

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What is the slope of the line that contains the points (-3,5)and (-5,6)
tigry1 [53]
<span>(-3,5) (-5,6)
slope = 5-6 / -3 --5
</span><span>slope = -1 / 2

</span>
6 0
3 years ago
What is the equation of a line with slope −23 and a y-intercept of −4 ?
Alona [7]

Answer:

its A

Step-by-step explanation:

the y intercept would be -4 and the slope would be -23, put it in y=mx+b form

8 0
3 years ago
Write an explicit formula for an , the nth term of the sequence 29, 19, 9, ....
Anna35 [415]

Answer:

a_{n} = 39 - 10n

Step-by-step explanation:

There is a common difference between consecutive terms , that is

19 - 29 = 9 - 19 = - 10

This indicates the sequence is arithmetic with nth term ( expicit formula )

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 29 and d = - 10 , then

a_{n} = 29 - 10(n - 1) = 29 - 10n + 10 = 39 - 10n

6 0
3 years ago
I don’t understand, help me out
Vikki [24]

Answer:

a. 76 b. 52

Step-by-step explanation:

The perimeter of a rectangle is the sum of its four sides.

Now all rectangles have a width and a length.

To find the perimeter it is 2 width + 2 length or 2W +2L.

So if the Perimeter P = 344 and Width W = 76 and P = 2W + 2L

Then...

2(76) + 2L = 344 multiply 2 and 76

2L + 152 = 344 subtract 152 from both sides

2L = 192 divide both sides by 2

L = 96

The length is 96.

The equation of an area of a rectangle is A or  area = width x length or W x L

So the equation is A = W x L

If the area is 4732 and the length is 91 then

91W = 4732 divide both sides by 91

W = 52

The width is 52.

Hope that helps, good luck with your homework!

7 0
3 years ago
Find the focus. y= -1/12 (x)² - 6
jolli1 [7]

Answer:

\Large \boxed{\sf\ \  (0,-9) \ \ }

Step-by-step explanation:

Hello,

We know that when the parabola equation is

   y=a(x-h)^2+k

the vertex is (h,k) and the focus is

   (h,k+\dfrac{1}{4a})

Here, the equation is

   y=-\dfrac{1}{12}x^2-6

so

   a=-\dfrac{1}{12}\\\\h = 0\\\\k =-6

So,

k+\dfrac{1}{4a}=-6-\dfrac{12}{4}=-6-3=-9

Then, the focus is

\large \boxed{\sf\ \  (0,-9) \ \ }

I attached the graph, included the focus so that you can see it :-)

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0
3 years ago
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