Answer:
And we can do a similar procedure for the sea water:
And after convert the volume to m^3 we got:
And then the density for the mixture would be given by:
And replacing we got:
Step-by-step explanation:
For this case we can begin calculating the mass for each type of water:
And after convert the volume to m^3 we got:
And we can do a similar procedure for the sea water:
And after convert the volume to m^3 we got:
And then the density for the mixture would be given by:
And replacing we got:
Because there's no picture provided, I can just give two points in order to formulate the equation using the point-slope formula. The x is in years while the y is in percentage. Suppose point 1 is (2, 35) and point 2 is (7,80).
Point Slope Formula: y - y₁ = [(y₂ - y₁)/(x₂ - x₁)](x - x₁)
Substituting,
y - 35 = [(80 - 35)/(7 - 2)](x - 2)
y - 35 = 9(x - 2)
Answer:
The inequality x3 − 14x2 + 48x − 1,680 ≤ 0 can be used to find pool’s length.
⇒The water level in the pool cannot exceed 14 feet.
Step-by-step explanation:
The question is on inequalities
Given;
Length= x ft
depth= x-6 ft
Width= x-8 ft
volume ≤ 1680 ft³
Forming the inequality to find length x of the pool
Volume= base area × depth
base area × depth ≤ volume
x(x-8) × (x-6) = 1680
(x²-8x )(x-6) = 1680
x(x²-8x) -6 (x²-8x)=1680
x³-8x²-6x²+48x=1680
x³-14x²+48x=1680
x³-14x²+48x-1680 ≤ 0
⇒The water level in the pool cannot exceed 14 feet...why?
taking the value of x at maximum to be 17 according to the graph, then maximum depth will be;
d=x-6 = 17-6=11 ft
⇒11 ft is less than 14ft
The answer is x=70 degrees
Answer:
The volume of a rectangular pyramid is found using the formula: V = (1/3) × L × W × h, where L x W represents the base area of the rectangular pyramid and h represents its total height.
Step-by-step explanation: